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Free_Kalibri [48]
3 years ago
12

A sprain ?

Physics
2 answers:
Vinil7 [7]3 years ago
8 0
D.is a stretch and/or of ligament.
saw5 [17]3 years ago
5 0
The answer is C. I<span>s a stretch and/or tear of a ligament.</span>
You might be interested in
&gt;
tester [92]

The pressure exerted on the block on the ground in N/m² is 200N/m².

<h3>What is pressure?</h3>

The pressure is the amount of force applied per unit area.

Given is a 5000 Newton block rests on the ground over 25 m² of area.

Pressure p = Force/Area

Put the values, we get

p = 5000 /25

p = 200 N/m²

Hence, pressure exerted on the block on the ground is 200 N/m².

Learn more about pressure.

brainly.com/question/12971272

#SPJ1

4 0
2 years ago
The amplitude, or magnitude, of a sinusoidal source is the maximum value of the source. What is the amplitude of the voltage sou
liraira [26]

Answer:

<em>A = 0.05 V</em>

Explanation:

<u>Sinusoidal Functions</u>

A sinusoid or sinusoidal function is a sine or cosine which general equation is

F(x)=A.sin(wt-\phi)

Or also

F(x)=A.cos(wt-\phi)

Where A is the amplitude or maximum value, w is the angular frequency, t is the time and \phi is the phase shift.

Comparing the given expression with the general formula

v(t)=50cos(2000t-45^o) mV

We can establish that A=50 mV = 0.05 V

A = 0.05\ V

7 0
3 years ago
(TIMED) Anyone know the answer to this question?
KengaRu [80]

I believe C is your answer (also, I am also using tht same exact program!)

7 0
3 years ago
Read 2 more answers
HELP ASAP <br> Describe when contact metamorphism occurs?
diamong [38]

Contact metamorphism occurs adjacent to igneous intrusions and results from high temperatures associated with the igneous intrusion. Since only a small area surrounding the intrusion is heated by the magma, metamorphism is restricted to the zone surrounding the intrusion, called a metamorphic or contact aureole

5 0
3 years ago
Read 2 more answers
A transformer is intended to decrease the value of the alternating current from 500 amperes to 25 amperes. The primary coil cont
EastWind [94]

Answer:

The number of turns in secondary coil is 4000

Explanation:

Given:

Current in primary coil I_{P} = 500 A

Current in secondary coil I_{S} = 25 A

Number of turns in primary coil N_{P} = 200

In case of transformer the relation between current and number of turns is given by,

     \frac{N_{S} }{N_{P}  } = \frac{I_{P} }{I_{S} }

For finding number of turns in secondary coil,

     N_{S} = \frac{I_{P} }{I_{S} }  N_{P}

     N_{S} = \frac{500}{25} \times 200

     N_{S} = 4000

Therefore, the number of turns in secondary coil is 4000

5 0
3 years ago
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