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3 years ago

N2 + 3H2 → 2NH3

Chemistry

1 answer:

lana66690 [7]3 years ago

4 0

The number of moles of H₂ that are needed to react with 2.0 moles of N₂ is 6.0 moles

<u><em>calculation</em></u>

N₂ +3H₂→ 2NH₃

The moles of H₂ is calculated using the mole ratio

That is from equation above N₂:H₂ is 1 :3

therefore the moles of H₂ = 2.0 moles x (3/1) = 6.0 moles

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Why do covalent compounds tend to be squishy?

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2 years ago

Automotive airbags inflate when a sample of sodium azide, NaN3, is very rapidly decomposed.

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Answer:

148 g

Explanation:

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2 NaN₃ ⇒ 2 Na + 3 N₂

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95.8 g × 1 mol/28.01 g = 3.42 mol

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2 years ago

In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce ga

VashaNatasha [74]

The question is incomplete, complete question is :

In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce gaseous ammonia. This reaction is now the first step taken to make most of the world's fertilizer. Suppose a chemical engineer studying a new catalyst for the Haber reaction finds that 348 liters per second of dinitrogen are consumed when the reaction is run at 205°C and 0.72 atm. Calculate the rate at which ammonia is being produced.

Answer:

The rate of production of ammonia is 217.08 grams per second.

Explanation:

$N_2+3H_2\rightarrow 2NH_3$

Volume of dinitrogen used in a second = 348 L

Temperature of the gas = T = 205°C = 205+273 K = 478 K

Pressure of the gas = P = 0.72 atm

Moles of dinitrogen = n

$n=\frac{PV}{RT}=\frac{0.72 atm\times 348 L}{0.0821 atm L/mol K\times 478 K}=6.385 mol$

According to reaction, 1 mole of dinitriogen gives 2 mole of ammonia.Then 6.385 moles of dinitrogen will give:

$\frac{2}{1}\times 6.385 mol=12.769 mol$

Mass of 12.769 moles of ammonia;

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217.08 grams of ammonia is produced per second.So, the rate of production of ammonia is 217.08 grams per second.

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3 years ago

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Vesna [10]

Answer:

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3 years ago