Answer:
267.57 kPa
Explanation:
Ideal gas law:
PV = n RT R = 8.314462 L-kPa/K-mol
P (16.5) = 1.5 (8.314462)(354) P = 267.57 kPa
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This is the answer
The elements potassium and sodium have similar chemical properties because they have the same number of valence electrons and form +1 ions.
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The answer is-
is octahedral in electronic and molecular geometry with 6 Fluorine atoms bonded to central atom S.
Lewis structures are the diagrams in which the valence electrons of the atoms of a compound are arranged around the atoms showing the bonding between the atom and the lone pair of electrons existing in the molecule.
Determine the molecular geometry of
.
- Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
- According to this theory, electrons are arranged around the central atom of the molecule in such a way that there is minimum electrostatic repulsion between these electrons.
- Now, calculate the total number of valence electrons in
.

Valence electrons of S = 6
Valence electrons of F = 7
Thus, the valence electrons in
are-

- The Lewis structure of
is - (Image attached). - In the structure, the number of atoms bonded to central atom (S) = 6.
- Number of non-bonding electron pairs on the central atom = 0 (as all the valence electrons are bonded to F).
- Electronic geometry in case of 6 bond pairs is octahedral.
- Molecular geometry us also octahedral with bond angles 90°.
- Central atom is sp3d2 hybridised.
is a non-polar molecule.
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Boyle's law states that pressure is inversely proportional to volume of gas at constant temperature
PV = k
where P - pressure , V - volume and k - constant
P1V1 = P2V2
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
substituting these values in the equation
1.25 atm x 0.75 L = P x 1.1 L
P = 0.85 atm
final pressure is B) 0.85 atm
<h3>
Answer:</h3>
812 kPa
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Explanation:</h3>
- According to Boyle's law pressure and volume of a fixed mass are inversely proportional at constant absolute temperature.
- Mathematically,

At varying pressure and volume;
P1V1=P2V2
In this case;
Initial volume, V1 = 2.0 L
Initial pressure, P1 = 101.5 kPa
Final volume, V1 = 0.25 L
We are required to determine the new pressure;

Replacing the known variables with the values;

= 812 kPa
Thus, the pressure of air inside the balloon after squeezing is 812 kPa