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3 years ago

If two is company and three is a crowd, what is 4 and 5?

Physics

2 answers:

REY [17]3 years ago

8 0

a mob i guess :_) uwuwuwuwuwu

LiRa [457]3 years ago

4 0

4 and 5 is 9

(4 + 5)

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Please I need help with these 2 questions. Thank you.

Lemur [1.5K]

First one is D and Second one is B

7 0

3 years ago

Suppose you run into a wall at 4.5 meters per second (about 10 mph). Let's say the wall brings you to a complete stop in 0.5 sec

STatiana [176]

Answer with Explanation:

We are given that

Initial velocity,u=4.5 m/s

Time=t =0.5 s

Final velocity=v=0m/s

We have to find the deceleration and estimate the force exerted by wall on you.

We know that

Acceleration= $\frac{v-u}{t}$

Using the formula

Acceleration= $a=\frac{0-4.5}{0.5}$

deceleration=a= $-9m/s^2$

We know that

Force =ma

Using the formula and suppose mass of my body=m=40 kg

The force exerted by wall on you

Force= $40\times (9)=360N$

3 0

3 years ago

Time running out plzz hurry!!!!!!

Vesnalui [34]

I think you would hear a lower pitch

3 0

3 years ago

Read 2 more answers

Which of the following are physical properties of nonmetals? a. they are brittle in the solid form b. most are gases at room tem

Black_prince [1.1K]

Option (D) is correct that all of the above are physical properties of non metals.

#$# THANK YOU #$#

6 0

3 years ago

Read 2 more answers

A wedge shaped air film is made between two sheets of glass using a spacer at one end of the glass sheets. If light of wavelengt

pychu [463]

Answer:

1178 nm

Explanation:

We are given that

Wavelength of light= $\lambda=589nm=589\times 10^{-9} m$

$1nm=10^{-9} m$

We have to find the thickness of spacer if five dark fringes are observed between the edges of the glass.

Suppose that first dark fringe and fifth dark fringe near spacer, then the path length of light is 4 times the wavelength of light.

The light passes through air film is two times then the change in air film thickness from one edge to other is two times the wavelength of light.

Change in air film thickness from one edge to other edge is same as the thickness of spacer.

Therefore, thickness of spacer= $2\lambda$

Thickness of spacer= $2\times 589\times 10^{-9}$ m

Thickness of spacer=1178 nm

Hence, the thickness of spacer=1178 nm

8 0

3 years ago