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3 years ago

Enter an expression for the force constant for the floating raft, in terms of L, g, and the density of water, ρ.

Physics

1 answer:

andriy [413]3 years ago

3 0

Answer:

K = ρL²g

Explanation:

Consider L as the length of the raft inside the water when the raft is displaced through additional distance y;

Then:

F = upthrust ( restoring force) = weight of the liquid displaced.

$F = V_{\omega} \rho_{\omega} g= A y \rho_{\omega} g$

where;

A = L²

$\rho_{\omega} = \rho$

F = ky.

Then,

$Ay \rho g = ky$

$L^2y \rho g = ky$

Divide both sides by y

K = ρL²g

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3 years ago

A car is going south on I-69 at 33 m/s (74 mph). The car has good brakes so its maximum braking acceleration is – 8.5 m/s^2 . Tr

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Answer:

1.69515 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

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2 years ago

jenny's model train is set up on a circular track. There are six telephone poles evenly spaced around the track. It takes the en

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Answer:

T = 60 s

Explanation:

There are 6 poles on the track which are equally spaced

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$\theta = \frac{2\pi}{6}$

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so the angular speed of the train is given as

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3 years ago

A small car has a head-on collision with a large truck. Which of the following statements concerning the magnitude of the averag

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Answer:

The small car and the truck experience the same average force.

Explanation:

Here we need to remember two of Newton's laws.

The second one says that:

F = m*a

force equals mass times acceleration.

And the third one says that;

"If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A"

From the third law, if the car experiences a force F due to the impact with the truck, then the truck experiences the same force F due to the impact.

But this seems odd, because we would expect to see the car being more affected by the impact, right?

Well, this is explained by the second law.

Suppose that the mass of the car is m, and the mass of the truck is M.

such that M > m

Then for the small car we have:

F = m*a

And for the truck:

F = M*a'

Because the force is the same for both of them, we can write:

m*a = M*a'

a = (M/m)*a'

because M > m, then M/m > 1.

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2 years ago

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3 years ago

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