Answer:
8.756 rad/s²
Explanation:
Given that:
A motorcycle accelerates uniformly from rest, then initial velocity v_i = 0 m/s
It final velocity v_f = 24.8 m/s
time (t) = 9.87 s
radius (r) of each tire = 0.287 m
Firstly; the linear acceleration of the motor cycle is determined as follows:
=(V_f - v_i)/t
=(24.8-0)/9.87
=2.513 m/s²
Then; the magnitude of angular acceleration
α = /r
=2.513/0.287
=8.756 rad/s²
I believe it's the the third one. :)
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The cannon is 17.69 m above the ground level
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Horizontal speed (u) = 333 m/s
- Horizontal distance (s) = 622 m
- Height (h) =?
<h3>How to determine the time </h3>
We'll begin by calculating the time taken for the ball to land on the ground. This can be obtained as follow:
- Horizontal speed (u) = 333 m/s
- Horizontal distance (s) = 622 m
- Time (t) =?
s = ut
622 = 333 × t
Divide both sides by 333
t = 622 / 333
t = 1.9 s
<h3>How to determine the height</h3>
The height of the cannon above the ground can be obtained as illustrated below:
- Acceleration due to gravity (g) = 9.8 m/s²
- Time (t) = 1.9 s
- Height (h) =?
h = ½gt²
h = ½ × 9.8 × 1.9²
h = 4.9 × 3.62
h = 17.69 m
Learn more about motion under gravity:
brainly.com/question/20385439
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