Answer:
Explanation:
His Kinetic energy = 1/2 m v^2
v = 5 m/s
m = 75 kg
Ke = 1/2 75 * 5^2
Ke = 937.5 Joules
This will be converted to PE when he reaches the maximum height he reaches. In other words KE = PE
PE = m * g * h
m = 75
g = 9.81
h = ?
PE = 937.5
937.5 = 75 * 9.81 * h
937.5 = 735.75 * h
937.5/735.75 = h
h= 1.27 meters
Answer:
The work done by the gravel to stop the truck is 520.44 kJ
Explanation:
<u>Step 1</u>: Data given
Mass of the truck = 3047.8 kg
The ramp has an angle of 9.5 °
Velocity of the truck = 20.68 m/s
distance = 26.6 meters
<u>Step 2:</u> Calculate initial kinetic energy
sin 9.5° = 0.165
h = ℓ*sin 9.5° = 26.6*0.165= 4.39 m
Ek = 1/2m*Vo² = 1/2*3047.8*20.68² = 651714.7 Joule = 651.7 kJ = initial kinetic energy
<u>Step 3: </u>Calculate potential energy
Epot = U = m*g*h = 3047.8*9.81*4.39 = 131256.25 Joule = 131.26 kJ
<u>Step 4:</u> What work is done by the truck on the gravel?
Frictional energy Ef = 651.7 kJ - 131.26 kJ = 520.44 kJ
Given the speed and the distance, to find time you can use the formula speed is equal to distance over time. From there you can manipulate the equation for time to equal the distance divided by speed. Time is equal to 18.4 meters divided by 35m/s which equals 0.526 seconds.
Answer:
d. 2 hours
Explanation:
because if it travels 100 miles per hour in 1 hour it would travel 200 miles in 2 hours and so fourth.
