<span>NaOH + HCl → NaCl + H2O
1 mol 1 mol
</span>2.75 × 10⁻⁴ mol 2.75 × 10⁻⁴ mol
M(H2O) = 2*1.0 +16.0 = 18.0 g/mol
2.75 × 10⁻⁴ mol H2O * 18.0 g H2O/1 mol H2O = 4.95*10⁻³ g H2O
Answer:
the relative molecular mass of hydrated iron (II) sulfate FeSO4.7H2O is 278.02
Explanation:
Chlorine because it lacks one valence electron to fill it's outer shell
The pH of a neutral aqueous solution at 37°C is 6.8.
<h3>What is Kw? </h3>
Kw is defined as the dissociation, which is also known as self-ionization, constant of water. this is an equilibrium constant, and its expression is:
Kw = [OH⁻] . [H₃O⁺]
Neutral pH determines that the concentrations of OH⁻ and H₃O⁺ are equal.
<h3>Calculation</h3>
Let us suppose concentration of OH and H₃O⁺ is x, to calculate it:
Kw =[OH⁻] . [H₃O⁺] = x²
x² = 2.4 × 10⁻¹⁴ M²
x = 1.5919 × 10⁻⁷ M
Hence, the concentration of OH and H₃O⁺ (x) = [H₃O⁺] = [OH⁻] = 1.5919×10⁻⁷ M
pH = -log[H₃O⁺] = -log( 1.5919×10⁻⁷ M)
pH = 6.8
Thus, we find that the pH of a neutral aqueous solution at 37 °c (which is the normal human body temperature) is 6.8.
learn more about pH:
brainly.com/question/9529394
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