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3 years ago

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A sample of an ideal gas has its volume doubled while its temperature remains constant. If the original pressure was 100 torr, w

hat is the new pressure?

1 answer:

Leviafan [203]3 years ago

6 0

PV = constant

V doubles, P will become half

New pressure = 100/2 = 50 torr

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Use the ΔHrxn values of the following reactions: 2SO2(g) + O2(g) → 2SO3(g) ΔHrxn = –196 kJ 2S(s) + 3O2(g) → 2SO3(g) ΔHrxn = –790

sesenic [268]

<u>Answer:</u> The $\Delta H^o_{rxn}$ for the reaction is -297 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

$S(s)+O_2(g)\rightarrow SO_2(g)$ $\Delta H^o_{rxn}=?$

The intermediate balanced chemical reaction are:

(1) $2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$ $\Delta H_1=-196kJ$

(2) $2S(g)+3O_2(g)\rightarrow 2SO_3(g)$ $\Delta H_2=-790kJ$

The expression for enthalpy of the reaction follows:

$\Delta H^o_{rxn}=\frac{[1\times (-\Delta H_1)]+[1\times \Delta H_2]}{2}$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=\frac{[(1\times -(-196))+(1\times (-790))}{2}=-297kJ$

Hence, the $\Delta H^o_{rxn}$ for the reaction is -297 kJ.

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3 years ago

For the wild type (unmutated) enzyme, you measure a rate of p-nitrophenol release by the change in absorbance at 405 nm (for the

Aleks04 [339]

Answer:

1.2x10⁻⁵M = Concentration of the product released

Explanation:

Lambert-Beer's law states the absorbance of a solution is directly proportional to its concentration. The equation is:

A = E*b*C

<em>Where A is the absotbance of the solution: 0.216</em>

<em>E is the extinction coefficient = 18000M⁻¹cm⁻¹</em>

<em>b is patelength = 1cm</em>

<em>C is concentration of the solution</em>

<em />

Replacing:

0.216 = 18000M⁻¹cm⁻¹*1cm*C

<h3>1.2x10⁻⁵M = Concentration of the product released</h3>

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3 years ago

A reaction between liquid reactants takes place at −10.0°C in a sealed, evacuated vessel with a measured volume of 45.0L. Measur

maks197457 [2]

Answer: 0.0624 atm

Explanation:-

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = ?

V= Volume of the gas = 45.0 L

T= Temperature of the gas = -10.0°C = 263 K $0^00C=273K$

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas

Moles of gas= $\frac{\text{ given mass}}{\text{ molar mass}}= \frac{19.0g}{146g/mole}=0.130moles$

$P=\frac{nRT}{V}=\frac{0.130\times 0.0821\times 263}{45.0}=0.0624atm$

The pressure of sulfur hexafluoride gas in the reaction vessel after the reaction is 0.0624 atm

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3 years ago

What kinds of materials can laboratories test?

Jet001 [13]

All. It depends on the lab setup, equipment, and expertise.

7 0

4 years ago

Given the NaOH density =1.0698g mL^-1, How many mL of .71M HCl would be required to neutralize 11.33g of 2.03 M NaOH?

SSSSS [86.1K]

The volume in ml of 0.71 M HCl that would be required to neutralize 11.33 g of 2.03 M NaOH is 30.3 ml

<u><em>calculation</em></u>

Step 1 : write equation for reaction

NaOH + HCl →NaCl +H₂O

Step 2:find the volume of NaOH

volume=mass/ density

= 11.33 g/ 1.0698 g/ml =10.59 ml

Step 3: find the moles of NaOH

moles = molarity x volume in liters

molarity= 2.03 M=2.03 mol/l

volume in liters =10.59/1000 =0.0106 L

moles = 2.03 M x 0.0106 L =0.0215 moles

step 4: use the mole ratio to determine the moles of HCl

from equation in step 1 , NaOH:HCl is 1:1 therefore the moles of HCl is also 0.0215 moles

Step 5: find volume of HCl

volume= moles/ molarity

molarity =0.71 M =0.71 mol/l

=0.0215 moles /0.71 mol/l=0.0303 L

into ml =0.0303 x 1000=30.3 ml

3 0

3 years ago