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Alona [7]
4 years ago
6

What is the resultant displacement of the two vectors below?

Physics
1 answer:
andriy [413]4 years ago
4 0

Answer:

C 3.6 cm, 56 degrees North of the East axis

Explanation:

The two vectors are perpendicular to each other, so we can find the magnitude of their resultant simply by using the Pythagorean theorem:

R=\sqrt{A^2+B^2}

where

A = 2.0 cm is the magnitude of the first vector

B = 3.0 cm is the magnitude of the second vector

Substituting,

R=\sqrt{2^2+3^2}=3.6 cm

Now we have to find the angle. If we measure the angle as North of East, the tangent of the angle is equal to the ratio between the component along North and the component along East. Therefore, in this case:

tan \theta = \frac{B}{A}=\frac{3}{2}=1.5\\\theta = tan^{-1}(1.5)=56.3 \sim 56^{\circ}

So, 56 degrees North of East.

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A bird flies overhead from where you stand at an altitude of 270.0ĵ m and at a velocity horizontal to the ground of 14.0î m/is.
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Answer:

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r = 270 ĵ m

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8 0
3 years ago
Which one is correct:
alisha [4.7K]

Answer:

Option (c) is correct.

Explanation:

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Where

u and v are initial and final velocity

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(v-u) is also called the change in velocity

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3 0
3 years ago
Why is the following situation impossible? Two identical dust particles of mass 1.00 µg are floating in empty space, far from an
Igoryamba

Answer:

This is a conceptual problem so I will try my best to explain the impossible scenario. First of all the two dust particles ara virtually exempt from any external forces and at rest with respect to each other. This could theoretically happen even if it's difficult for that to happen. The problem is that each of the particles have an electric charge which are equal in magnitude and sign. Thus each particle should feel the presence of the other via a force. The forces felt by the particles are equal and opposite facing away from each other so both charges have a net acceleration according to Newton's second law because of the presence of a force in each particle:

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Having seen Newton's second law it should be clear that the particles are actually moving away from each other and will not remain at rest with respect to each other. This is in contradiction with the last statement in the problem.

4 0
3 years ago
The area of a circular trampoline is 108.94 square feet. What is the radius of the trampoline? Round to the nearest hundredth.
djverab [1.8K]
The correct answer to this question is this one: B. 5.89 feet
<span>The area of a circular trampoline is 108.94 square feet. The radius of the trampoline is 5.89 feet.
</span>
For a circle,
A = (pi)r^2
108.94 ft^2 = (pi)r^2
r^2 = (108.94 ft^2)/(pi)
r = sqrt(108.94/pi) ft
r = 5. 89 ft
8 0
3 years ago
Read 2 more answers
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