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AfilCa [17]
3 years ago
12

A lamp has the shape of a parabola when viewed from the side. The lamp is centimeters wide and centimeters deep. How far is the

light source from the bottom of the lamp if the light source is placed at the focus

Physics
1 answer:
andrew-mc [135]3 years ago
8 0

The question is not complete so i have attached it.

Answer:

The light source is 2 cm from the bottom of the lamp

Explanation:

From the attached image, we can see that the parabola opens up with its vertex at the origin.

Now, the standard form of equation for a parabola is:

x² = 4ay

Looking at the parabola in the attachment, the top right edge of the lamp has a coordinate of (12,18)

Thus, we have;

12² = 4a(18)

144 = 72a

a = 144/72

a = 2

Looking at the parabola again, the line of symmetry is at x = 0

Thus, axis of symmetry is at x = 0.

Thus, focus is at (0, 2)

So, if the light source is placed at the focus, the distance of the light source from the bottom of the lamp is 2 cm

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4 0
2 years ago
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Andreyy89

Answer:

 B. twice as much kinetic energy

Explanation:

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We know that velocity of particle does not depends on their mass that is the velocity of both mass will be same after dropping from the roof.

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7 0
3 years ago
In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is appro
blondinia [14]
In order to answer these questions, we need to know the charges on
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I'm beginning to get the creepy feeling that, in return for the generous
5 points, you also want me to go and look these up so I can use them
in calculations ... go and collect my own straw to make the bricks with,
as it were. 

Ok, Rameses:

Elementary charge . . . . .  1.6 x 10⁻¹⁹  coulomb
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          =     ( -2.304 x 10⁻²⁸) / (5.35 x 10⁻¹¹)²

          =          8.05 x 10⁻⁸  Newton .


b).  Centripetal acceleration  = 

                                               v² / r  .

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That's an enormous acceleration ... about  7.85 x 10²¹  G's !
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It would be so easy to check this work of mine ...
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I didn't use either answer to find the other one, and I didn't use  "  F = MA "
either.

I could just take the ' F ' that I found, and the 'A' that I found, and the
electron mass that I looked up, and mash the numbers together to see
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I'm going to leave that step for you.   Good luck !
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Answer:

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