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OverLord2011 [107]
3 years ago
14

How are the electric field lines around a positive charge affected when a second positive charge is near it?

Physics
1 answer:
Liono4ka [1.6K]3 years ago
8 0

Answer:Because it likes to repel and attract opposites

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An object has a variable volume and shape before it changes state. After the
monitta
A : Solid to liquid


Solids have a variable volume and shape before it changed. Liquids can change in shape but have a fixed volume ( ex: water holding it’s shape in the cup until the person spills it )
3 0
3 years ago
Read 2 more answers
A student throws a baseball upwards at an angle of 60 degrees to the horizontal. The initial horizontal and vertical components
frez [133]

Given data

ball throws upwards at an angle 60°

Horizontal component (Vh) = 12.5 m/s,

Vertical component (Vv) = 21.7 m/s ,

The magnitude of throw/resultant velocity (V) = ?

The resultant velocity /the velocity with which ball is throws is determined by the following equation

                                   V = √[(Vh)² + (Vv)²]

                                       = √[(12.5)² + (21.7)²]

                                      = 25.04 m/s

<em>                 The resultant velocity or the velocity with which the ball is thrown is 25 m/s</em>


4 0
3 years ago
Explain the microsoft word skills you are most confident in performing.<br><br>​
Sladkaya [172]
Yes this is not gonna work
4 0
2 years ago
A surveyor measures the distance across a river that flows straight north by the following method. Starting directly across from
bearhunter [10]

Answer:

The width of the river is  z = 60.62 \ m

Explanation:

From the question we are told that

     The distance of the base line is D = 130 m

       The angle is  \theta =  25^o

A diagram illustration the question is shown on the first uploaded image

    Applying Trigonometric Rules for Right-angled Triangle,

            tan  25 =  \frac{z}{130}

Now making  z the subject

           z = 130 * tan (25)

          z = 60.62 \ m

8 0
2 years ago
A moto-cross motorcycle/rider is airborne after a jump. Each wheel of his bike has a rotational inertia of 0.760 kg m2, so the p
Debora [2.8K]

Answer:2.17 rad/s

Explanation:

Given

Each wheel has moment of inertia I=0.76 kg-m^2

Linear speed speed v=15 m/s

angular speed of tire \omega =50 rad/s

moment of inertia of motorcycle I_2=35 kg-m^2

Initial moment of inertia I_1=2\times 0.76=1.52 kg-m^2

Due to absence of external Torque we can Conserve Angular Moment of inertia

l_1\omega _1=I_2\cdot \omega _2

2\times 0.76\times 50=35\times \omega _2

\omega _2=2.17\ rad/s

6 0
3 years ago
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