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OverLord2011 [107]
3 years ago
14

How are the electric field lines around a positive charge affected when a second positive charge is near it?

Physics
1 answer:
Liono4ka [1.6K]3 years ago
8 0

Answer:Because it likes to repel and attract opposites

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A football is kicked into the air from an initial height of 4 feet. The height, in feet, of the football above the ground is giv
kakasveta [241]

Answer: 0.5 seconds or 2.625 seconds

Explanation:

At t = 0, The ball is 4 ft above the ground.

The height of the football varies with time in the following way:

s(t) = -16 t² + 50 t + 4

we need to find the time in which the height would of the football would be 25 ft:

⇒25 = -16 t² + 50 t + 4

we need to solve the quadratic equation:

⇒ 16 t² - 50 t + 21 = 0

t = \frac{50 \pm \sqrt{50^2-4\times 16\times 21}}{2\times16}

⇒ t = 0.5 s or 2.625 s

Therefore, at t = 0.5 s or 2.625 s, the football would be 25 ft above the ground.

3 0
3 years ago
Read 2 more answers
What is the reaction force to a foot pushing down on the floor?
Helga [31]

Answer:

C. The floor pushing back against the foot​

Explanation:

5 0
3 years ago
Read 2 more answers
4. Find the uniform acceleration that causes a car’s velocity to change from 32m/s to
GrogVix [38]

Answer:

a=8\ m/sec^2

Explanation:

we know that

The formula  to calculate the acceleration is

a=\frac{V_2-V_1}{t}

we have

V_2=96\ m/sec

V_1=32\ m/sec

t=8\ sec

substitute

a=\frac{96-32}{8}

a=8\ m/sec^2

4 0
4 years ago
The volume flow rate of blood leaving the heart to circulate throughout the body is about 5 L/min for a person at rest. All this
skelet666 [1.2K]

Answer:

n=2.9\times 10^9

A=1.88\times 10^{-8}\ m^2

Explanation:

Given that

Q= 5 L/min

1 L = 10⁻³ m³/s

1 min = 60 s

Q=0.083 x 10⁻³ m³/s

d= 6 μm

v= 1 mm/s

So the discharge flow through one tube

q = A v

A=\dfrac{\pi}{4}d^2

A=\dfrac{\pi}{4}\times (6\times 10^{-6})^2\ m^2

A=2.8 x 10⁻¹¹ m²

v= 1 x 10⁻³  m/s

q= 2.8 x 10⁻¹⁴  m³/s

Lets take total number of tube is n

Q= n q

n=Q/q

n=\dfrac{0.083\times 10^{-3} }{ 2.8\times 10^{-14}}

n=2.9\times 10^9

Surface  area A

A= π d L

A=\pi \times 6\times 10^{-6}\times 10^{-3}\ m^2

A=1.88\times 10^{-8}\ m^2

7 0
3 years ago
Two magnets are sliding towards each other. One of the magnets, which has a mass of 125 grams, is moving in the positive x-direc
olasank [31]

Answer:

0.45 m/s in the negative x-direction

Explanation:

From the law of conservation of momentum, the sum of initial momentum equals the sum of final momentum

Momentum, p=mv where m is the mass and v is the velocity

m_1v_1+m_2v_2=(m_1+m_2)v_c where v_c is the common velocity, v_1 and v_2 are velocities of magnet moving in positive x-direction and magnet moving in negative x-direction respectively, m_1 and m_2 are masses of magnet moving in positive x-direction and magnet moving in negative x-direction respectively.

Substituting 125 g for m_1 and 85 g for m_2, 7.33 m/s v_1, -11.9 m/s for v_1 then

125 g\times 7.33 m/s + (85 g\times -11.9)=(125 g+ 85 g)\times v_c

-95.25 g. m/s=210 g v_c

v_c=\frac {-95.25 g.m/s}{210 g}=-0.453571429 m/s
\approx -0.45 m/s

Therefore, the velocity of single unit is 0.45 m/s in the negative x-direction

5 0
3 years ago
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