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OverLord2011 [107]
3 years ago
14

How are the electric field lines around a positive charge affected when a second positive charge is near it?

Physics
1 answer:
Liono4ka [1.6K]3 years ago
8 0

Answer:Because it likes to repel and attract opposites

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A series of evenly timed pulses create a wave that can be described as a _______<br><br> wave.
son4ous [18]

Answer:

Periodic

Explanation:

A periodic (or repetitive) wave has continuously repeating pattern with characteristics such as amplitude, wavelength and frequency. In a periodic wave, a series of pulses that are evenly timed would be created. In other words, the wave pattern in a periodic wave repeats at regular intervals.

An example of a periodic wave is the sound from the strings of a violin.`

8 0
3 years ago
What velocity must a 1210 kg car have in order to have the same momentum as a pickup truck
Mariulka [41]

Answer: 46.5 m/s

Explanation:

Momentum = mass(m) × velocity (v)

momentum of car = momentum of truck

1210 × v = 2250 × 25

v = 46.5 m/s

6 0
3 years ago
When a man travel from hilly to terai what will happen to weight and why?
juin [17]

Answer:

When a man travels from Hilly region to Terai region, his weight gradually increases because the value of g is more at the Terai region than that in hilly region. 3. An object weights 20 N in air and 16 N in liquid, then answer the following questions.

Explanation:

because the value of g is more at the Terai region than that in hilly region. 3. An object weights 20 N in air and 16 N in liquid, then answer the following questions.

6 0
3 years ago
Plz help me plz its in the picture
natka813 [3]
Il write down the answers of the blanks which are as follows:-
Weight
Electrical
Magnetic
Force
Newtons
Mass
Kilograms

Hope this helps!
5 0
3 years ago
6) If a mass of an object is decreased to half and acting force is reduced by quarter the acceleration of its motion
Zepler [3.9K]

Answer:

Decreases to half.

Explanation:

From the question given above, the following data were obtained:

Initial mass (m₁) = m

Initial force (F₁) = F

Initial acceleration (a₁) =?

Final mass (m₂) = ½m

Final force (F₂) = ¼F

Final acceleration (a₂) =?

Next, we shall determine a₁. This can be obtained as follow:

F₁ = m₁a₁

F = ma₁

Divide both side by m

a₁ = F / m

Next, we shall determine a₂.

F₂ = m₂a₂

¼F = ½ma₂

2F = 4ma₂

Divide both side by 4m

a₂ = 2F / 4m

a₂ = F / 2m

Finally, we shall determine the ratio of a₂ to a₁. This can be obtained as follow:

a₁ = F / m

a₂ = F / 2m

a₂ : a₁ = a₂ / a₁

a₂ / a₁ = F/2m ÷ F/m

a₂ / a₁ = F/2m × m/F

a₂ / a₁ = ½

Cross multiply

a₂ = ½a₁

From the illustrations made above, the acceleration of the car will decrease to half the original acceleration

7 0
3 years ago
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