Answer:
Check the explanation
Explanation:
colligative property
a. let the salt in question is NaCl
to raise temperature of water from 95 to 100 oC
dTb = 100-95 = 5 oC
use,
dTb = iKbm = 5 oC
= 2 x 0.512 x grams NaCl/58.44 x 3.8
grams of NaCl salt needed = 1084.33 g
b. with,
1 cup = 273 g
thus,
amount of salt NaCl = 1084.33 g/273 = 3.97 cups (or 4 cups)
c. Yes, to raise the temperature of water by 5 oC the amount of salt needed for 3.8 kg water is reasonable.
Answer: Moles of solute particles are present in 272 mL solution of 0.242 M
are 0.0658.
Explanation:
Molarity is defined as the number of moles of solute dissolved per Liter of the solution.
To calculate the number of moles for given molarity, we use the equation:
.....(1)
Molarity of
solution = 0.242 M
Volume of solution = 272 mL
Putting values in equation 1, we get:
![0.242M=\frac{\text{Moles of}AlCl_3\times 1000}{272ml}\\\\\text{Moles of AlCl_3}=\frac{0.242mol/L\times 272}{1000}=0.0658mol](https://tex.z-dn.net/?f=0.242M%3D%5Cfrac%7B%5Ctext%7BMoles%20of%7DAlCl_3%5Ctimes%201000%7D%7B272ml%7D%5C%5C%5C%5C%5Ctext%7BMoles%20of%20AlCl_3%7D%3D%5Cfrac%7B0.242mol%2FL%5Ctimes%20272%7D%7B1000%7D%3D0.0658mol)
Thus moles of solute particles are present in 272 mL solution of 0.242 M
are 0.0658.
Answer:
The concentration of one or more of the products is small.
The reaction will not proceed very far to the right.
The reaction will generally form more reactants than products
Explanation:
We often write
K =[Products]/[Reactants]
Thus, if K is small
- We have fewer products than reactants
- We have more reactants than products
- The position of equilibrium lies to the left
A. is wrong. Usually, if K < 1, the concentration of reactants is greater than that of the products.
<span>E=hν</span> where E is the energy of a single photon, and ν is the frequency of a single photon. We recall that a photon traveling at the speed of light c and a frequency ν will have a wavelength λ given by <span>λ=<span>cν</span></span>λ will have an energy given by <span>E=<span><span>hc</span>λ</span></span><span>λ=657</span> nm. This will be <span>E=<span><span>(6.626×<span>10<span>−34</span></span>)(2.998×<span>108</span>)</span><span>(657×<span>10<span>−9</span></span>)</span></span>=3.0235×<span>10<span>−19</span></span>J</span>
So we now know the energy of one photon of wavelength 657 nm. To find out how many photons are in a laser pulse of 0.363 Joules, we simply divide the pulse energy by the photon energy or <span>N=<span><span>E<span>pulse </span></span><span>E<span>photon</span></span></span>=<span>0.363<span>3.0235×<span>10<span>−19</span></span></span></span>=1.2×<span>1018</span></span>So there would be <span>1.2×<span>1018</span></span><span> photons of wavelength 657 nm in a pulse of laser light of energy 0.363 Joules.</span>