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choli [55]
3 years ago
15

A scientific LAW has been proven and a THEORY has not. True Or False​

Physics
2 answers:
lara [203]3 years ago
7 0

Answer:

true

Explanation:

i did the test its right

taurus [48]3 years ago
3 0

Answer:

true

mark mine as brainiest, i could use the points

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Two air track carts move along an air track towards each other. Cart A has a mass of 450 g and moves toward the right with a spe
ra1l [238]

Answer:

0.465 kgm/s

Explanation:

Given that

Mass of the cart A, m1 = 450 g

Speed of the cart A, v1 = 0.85 m/s

Mass of the cart B, m2 = 300 g

Speed of the cart B, v2 = 1.12 m/s

Now, using the law of conservation of momentum.

It is worthy of note that our cart B is moving in opposite directions to A

m1v1 + m2v2 =

(450 * 0.85) - (300 * 1.12) =

382.5 - 336 =

46.5 gm/s

If we convert to kg, we have

46.5 / 100 = 0.465 kgm/s

Thus, the total momentum of the system is 0.465 kgm/s

6 0
4 years ago
Two uniform spheres,each of mass 0.260kg are fixed at points A and B
Ivan

Answer:

a) 2.76x10^-9 m/s^2

b) downward

Explanation:

a) In order to do this, we need to use the newton's law of gravitation which is:

F = G.m/r²

Where:

G: Constant of gravitation (6.67x10^-11 N/m)

m: mass of the object

r: distance or radius of the object.

In this case, we have two spheres, so this law becomes:

F = G*m1*m2 / r²

Now, you are not providing a picture with this, however, this problem is very similar to one I solved before, so, I'm gonna use the same values to solve this. If, you have different values for the distance, just replace them in this procedure and should get the correct and more accurate answer.

In this case, the distance that separates sphere in P from sphere A and B is 10 cm. As both spheres have the same mass and they are at the same distance from P, we can assume that F1 = F2 so:

F1 = (6.67x10^-11) * (0.01) * (0.26) / (0.1)² = 1.73x10^-11 N

sphere at P, will roll downward to the middle of sphere A and B. The distance between these two points it's 8 cm (See picture attached)

Now, according to my data, they are exerting a force in the y axis, so:

F1y = Fy * senФ

senФ using trigonometry is:

senФ = opposite lenght / hipotenuse

senФ = 8/10 = 0.8

Replacing:

F1y = 1.73x10^-11 * 0.8 = 1.38x10^-11 N

This force it's exactly the same as F2y, so the total force is:

F = 1.38x10^-11 * 2 = 2.76x10^-11 N

Finally, using the second law of Newton:

F = m*a

Solving for a:

a = F/m

replacing:

a = 2.76x10^-11 / 0.01

a = 2.76x10^-9 m/s²

According to the picture and the value of this magnitude, it's going downward.

3 0
3 years ago
What is an example of a chemical change that occurs as part of the rock cycle
kotykmax [81]
I am crossed between A and D but i think A is the correct one.
5 0
3 years ago
Read 2 more answers
Un bloque de 750 kg es empujado hacia arriba por una pista inclinada 15º respecto de la horizontal. El coeficiente de rozamiento
kotegsom [21]

Answer:

4776.98 N is the minimum force to start the rise.  

Explanation:

We can use the first Newton's law to find the minimum force to move the block.

So we will have:

F-W_{x}-F_{f}=0

Where:

  • F is the force
  • W(x) is the weight of the block in the x direction, W = mg*sin(15)
  • F(f) is the static friction force (F(f) = μN), μ is the static friction coefficient 0.4.

F=W_{x}+F_{f}=mgsin(15)+\mu N

F=mgsin(15)+\mu mgcos(15)

F=mg(sin(15)+\mu cos(15))

F=750*9.81(sin(15)+0.4*cos(15))

F=4776.98 N

Therefore 4776.98 N is the minimum force to move the block.

I hope it helps you!

8 0
3 years ago
When passing a construction zone, you should
Agata [3.3K]
B. is your answer because C. worker are gonna be too busy to instruct you.
D. what if their is no other way to get to your location.
A.you don't wanna rush because you might cause harm to someone.
hope this helps :)
4 0
3 years ago
Read 2 more answers
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