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natta225 [31]
3 years ago
15

Determine the binding energy of an F-19 nucleus. The F-19 nucleus has a mass of 18.99840325 amu. A proton has a mass of 1.00728

amu, a neutron has a mass of 1.008665 amu, and 1 amu is equivalent to 931 MeV of energy. Group of answer choices
Physics
1 answer:
Anvisha [2.4K]3 years ago
8 0

Answer:

Energy = 1.38*10^13 J/mol

Explanation:

Total number of proton in F-19 = 9

Total number of neutron in F-19 = 10

Expected Mass of F-19  

= 9*1.007 + 10*1.008 = 19.152 u

Actual  mass of F-19 = 18.998 u

Energy of one particle of F-19 = 931.5*Δm = 931.5*(19.152-18.998)

= 143.234 MeV

Energy of one mole of F-19 = 143.234*10^6*1.6*10^-19*6.022*10^23  

= 1.38*10^13 J/mol

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Answer:

1)

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F=qvB sin \theta

where here:

For the proton in this problem:

q=1.602\cdot 10^{-19}C is the charge of the proton

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F=(1.602\cdot 10^{-19})(300)(19)(sin 65^{\circ})=8.28\cdot 10^{-16} N

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The magnetic field produced by a bar magnet has field lines going from the North pole towards the South Pole.

The density of the field lines at any point tells how strong is the magnetic field at that point.

If we observe the field lines around a magnet, we observe that:

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4)

The radius of a particle moving in a magnetic field is given by:

r=\frac{mv}{qB}

where here we have:

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v=2155 m/s is the speed of the alpha particle

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B = 12.2 T is the strength of the magnetic field

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5)

The cyclotron frequency of a charged particle in circular motion in a magnetic field is:

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6)

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7)

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\Delta t is the time elapsed

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8)

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See the last 7 answers in the attached document.

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