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Ann [662]
3 years ago
11

SO2 + H2O ---> H2SO3

Chemistry
1 answer:
alexdok [17]3 years ago
8 0
This is the answer i for when I worked it out, it may be right and it may be wrong. I am currently in Pre-AP chem and we just learned this this week and I am in the same boat as you ahaha

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What is the easiest way to determine the reactivity of an element
makkiz [27]

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4 0
3 years ago
Which of the following keeps satellite in orbit
BabaBlast [244]

Answer:

Gravity

Explanation:

Without gravity it would just float in space.

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4 0
3 years ago
How many moles of silver chloride, produced from 100 g of silver nitrate reacting with barium chloride BaCl2?
Dmitrij [34]

Answer:

Equation of Reaction

2AgNO3 + BaCl2 === 2AgCl + Ba(NO3)2

Molar Mass of AgNO3 = 170g/mol

Moles of reacting AgNO3 = 100g/170gmol-¹

=0.588moles of AgNO3

From the equation of reaction...2moles of AgNO3 reacts to Produce 2Moles of Silver Chloride

So Their ratio is 2:2.

This means that 0.588Moles of AgCl Will be produced too.

ANSWER...0.588MOLES OF AgCl WILL BE PRODUCED.

7 0
3 years ago
Sodium carbonate (NaCO3) is sometimes used as a water-softening agent. Suppose that a worker prepares a 0.730 M solution of NaCO
elena55 [62]

Answer : The mass of solute in solution is 1.09\times 10^2g.

Solution : Given,

Molarity = 0.730 M

Volume of solution = 1.421 L

Molar mass of sodium carbonate = 105.98 g/mole

Formula used for Molarity :

Molarity=\frac{w}{M\times V}

where,

w = mass of solute

M = Molar mass of solute

V = volume of solution in liter

Sodium carbonate is solute and water is solvent.

Now put the given values in above formula, we get the mass of solute in solution.

0.730mole/L=\frac{w}{(105.98g/mole)\times (1.412L)}

By rearranging the terms, we get

m=109.247g=1.09\times 10^2g

Therefore, the mass of solute in solution is 1.09\times 10^2g.

4 0
3 years ago
How good are you with chemistry
Ugo [173]

Answer:

<h2>━☆゚.*・。゚Fine, but not as good</h2>
7 0
3 years ago
Read 2 more answers
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