All categories

3 years ago

The north magnetic pole of a compass magnet points towards earth's geographic _ and earth's magnetic _.

Physics

2 answers:

Pavel [41]3 years ago

7 0

The answer is
North pole; south pole
I hope this helps

vazorg [7]3 years ago

7 0

Answer:

The north magnetic pole of a compass magnet points towards earth's geographic <u>NORTH</u> and earth's magnetic <u>SOUTH</u>.

Explanation:

Like poles repel each other and unlike poles attract each other. A magnetic compass is based on this property of magnets. It has magnetic needle and it is known that every magnet has two poles - North pole and south pole. A compass is used find the directions. The needle points towards North. This north is actually the Earth's geographic north and would be magnetic south because south pole will attract north pole of the compass.

You might be interested in

An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.40 kW. A receiving antenna 6

lara [203]

To solve the problem we will apply the concepts related to the Intensity as a function of the power and the area, as well as the electric field as a function of the current, the speed of light and the permeability in free space, as shown below.

The intensity of the wave at the receiver is

$I = \frac{P_{avg}}{A}$

$I = \frac{P_{avg}}{4\pi r^2}$

$I = \frac{3.4*10^3}{4\pi(4*1609.34)^2} \rightarrow 1mile = 1609.3m$

$I = 6.529*10^{-6}W/m^2$

The amplitude of electric field at the receiver is

$I = \frac{E_{max}^2}{2\mu_0 c}$

$E_{max}= \sqrt{2I\mu_0 c}$

The amplitude of induced emf by this signal between the ends of the receiving antenna is

$\epsilon_{max} = E_{max} d$

$\epsilon_{max} = \sqrt{2I \mu_0 cd}$

Here,

I = Current

$\mu_0$ = Permeability at free space

c = Light speed

d = Distance

Replacing,

$\epsilon_{max} = \sqrt{2(6.529*10^{-6})(4\pi*10^{-7})(3*10^{8})(60.0*10^{-2})}$

$\epsilon_{max} = 0.05434V$

Thus, the amplitude of induced emf by this signal between the ends of the receiving antenna is 0.0543V

6 0

3 years ago

collision occurs betweena 2 kg particle traveling with velocity and a 4 kg particle traveling with velocity. what is the magnitu

anzhelika [568]

Answer:

metre per seconds

Explanation:

because velocity = distance ÷ time

4 0

3 years ago

how much work does tension do on the laptop as it moves 2.0 mm ? express your answer with the appropriate units.

8090 [49]

The work done by tension force of 14N applied on the laptop by a rope as it moves 2.0 mm up the slope is 0.028 J

W = F d cos θ

W = Work done

F = Force

d = Displacement

θ = Angle between force and displacement vector

F = 14 N

d = 2 mm = 0.002 m

θ = 0

W = 14 * 0.002 * 1

W = 0.028 J

Work done is the change in energy of an object. So if an object moves a certain distance, work is done on the object. If the force and displacement are perpendicular to each other there is no work done on the object.

Therefore, the work done by tension on the laptop is 0.028 J

To know more about work done

brainly.com/question/12834956

#SPJ4

8 0

1 year ago

What is the period of a wave that has a frequency of 300 hz?

Butoxors [25]

Answer:

T = 0.003 s

(Period is written as T)

Explanation: