Answer:
There is a relationship between the strength of an acid (or base) and the strength of its conjugate base (or conjugate acid): The stronger the acid, the weaker its conjugate base. The weaker the acid, the stronger its conjugate base. The stronger the base, the weaker its conjugate acid.
explanation
The strength of an acid and a base is determined by how completely they dissociate in water. Strong acids (like stomach acid) break down or dissociate in water. Weak acids maintains their protons in water.
Answer is: 2. dillute acids feel slipper.
1) Acids are corrosive is correct. For example hydrochloric acid (HCl) will react with most metals.
2) Dillute acids feel slippery is not correct. Bases, for example solution of sodium hydroxide feels slipery.
3) Acids have a distinctly sour taste is correct. For example, vinegar is mixture of acetic acid (CH₃COOH) and water (H₂O). Vinegar is colourless liquid with sour taste and pungent smell, freezing point of the vinegar is lower than glacial acetic acid.
4) Acids have more hydronium ions than hydroxide ions is correct. Because acid gives a lot of hydrogen cations (H⁺), pH (pH = -log[H⁺]) is lower than seven (acidic solution).
Answer:
B) Electrons are located in the cloud-like areas around the nucleus.
Explanation:
The quantum mechanical model of the atom does not consider the path through which an electron travels. It rather estimates the probability of where electrons can be found at each energy level.
The region of maximum probability of where an electron is located is sometimes called an electron cloud or orbital. Each orbital of an atom and the electrons accomodated are described completely by a set of four quantum numbers.
Answer:
The molarity of the solution: 0,27M
Explanation:
First , we calculate the weight of 1 mol of NaCl:
Weight 1mol NaCl= Weight Na + Weight Cl= 23 g+ 35, 5 g= 58, 5 g/mol
58,5 g---1 mol NaCl
64 g--------x= (64 g x1 mol NaCl)/58,5 g= 1, 09 mol NaCl
A solution molar--> moles of solute in 1 L of solution:
4 L-----1,09 mol NaCl
1L----x0( 1L x1,09 mol NaCl)/4L =0,27moles NaCl--->0,27M
Answer:
Therefore 500 ml of solution have 0.25 mol of NaCl .. = 14.61 g (ans.)
Explanation:
