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Greeley [361]
3 years ago
15

3. What exerts a greater force on the table of 2 kg book lying flat or a 2 kg book on its

Physics
1 answer:
Darina [25.2K]3 years ago
5 0

Answer:

A book on its side exerts a greater force.

Explanation:

Pressure = Force / Area

Assuming that 1kg = 10N

2kg = 20N

Area of book lying flat = 0.3m × 0.2m

                                     = 0.6m²

Pressure of book lying flat = 20N / 0.6m²

                                            = 30Pa (1 s.f.)

Area of book on its side = 0.2m × 0.05m

                                        = 0.01m²

Pressure of book on its side = 20N / 0.01m²

                                               = 2000Pa (1 s.f.)

Since 2000Pa (1 s.f.) > 30Pa (1 s.f.), a book on its side applies greater pressure than lying flat.

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Distance and direction of an objects change in position from starting point
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Explanation:

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3 years ago
The vertebral region is _________ to the scapular region.
Lisa [10]

Answer:

<em>The answer is medial!</em>

Explanation:

<em>The vertebral region is </em><u><em>medial</em></u><em> to the scapula.</em>

<em>Hope This Helps!</em>

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Time: distance: direction:velocity
juin [17]
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3 years ago
In an old-fashioned amusement park ride, passengers stand inside a 4.9-m-diameter hollow steel cylinder with their backs against
Viefleur [7K]

Answer:

24.07415 rpm

Explanation:

\mu = Coefficient of friction = 0.63

v = Velocity

d = Diameter = 4.9 m

r = Radius = \frac{d}{2}=\frac{4.9}{2}=2.45\ m

m = Mass

g = Acceleration due to gravity = 9.81 m/s²

Here the frictional force balances the rider's weight

f=\mu F_n

The centripetal force balances the weight of the person

\mu m\frac{v^2}{r}=mg\\\Rightarrow \mu \frac{v^2}{r}=g\\\Rightarrow v=\sqrt{\frac{gr}{\mu}}\\\Rightarrow v=\sqrt{\frac{9.81\times 2.45}{0.63}}\\\Rightarrow v=6.17656\ m/s

Velocity is given by

v=\omega r\\\Rightarrow \omega=\frac{v}{r}\\\Rightarrow \omega=\frac{6.17656}{2.45}\\\Rightarrow \omega=2.52104\ rad/s

Converting to rpm

2.52104\times \frac{60}{2\pi}=24.07415\ rpm

The minimum angular speed for which the ride is safe is 24.07415 rpm

4 0
3 years ago
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