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3 years ago

Part A:

2 answers:

8 0

Part A:
( 5,000 : 100 ) * 6 = 300 lit.
300 lit. * 1.066 Euros/ lit. = 318.9 Euros
1 Euro = 1.20 USD
318.9 * 1.20 = 382.68 USD

Part B :
6 lit./100 km = 0.06 lit/1 km
1 gal = 3.7853 lit.
1 mile = 1.609344 km
0.06 : 3.7853 = 0.01585
... = 0.01585 gal / 1 km / * 1.609344
= 0.0255 gal/mile

marissa [1.9K]3 years ago

3 0

(a). The fuel expense of the car in the complete trip in US dollars is $\boxed{\$\,354}$ .

(b). The fuel consumed in gallons per mile is $\boxed{0.0254\text{ gallons/mile}}$ .

Explanation:

Given:

The price of the fuel in Europe is $1.063\text{ euros/ltr}$ .

The amount of fuel required for every $100\text{ km}$ is $6.00\text{ ltr}$ .

Part (A):

Concept:

The value of one euro equivalent to the US dollar is $\$\,1.11$ .

The cost of the fuel in terms of the US dollar is:

$\begin{aligned}c&=1.063\text{ euros/ltr}\left(\dfrac{\$\,1.11}{1\text{ euro}}\right)\\&=\$\,1.18\text{ USD/ltr}\end{aligned}$

Since the car consumes $6\text{ ltr}$ of fuel during the journey of $100\text{ km}$ , the total fuel consumed by the car in the trip of $5000\text{ km}$ is:

$\begin{aligned}n&=\dfrac{6\text{ ltr}}{100\text{ km}}\times(5000\text{ km})\\&=300\text{ ltr}\end{aligned}$

The fuel consumed by the car in the whole trip of $5000\text{ km}$ is $300\text{ ltr}$ .

The fuel expense for the trip of $5000\text{ km}$ can be obtained as:

$\begin{aligned}\text{ cost}&=1.18\text{ USD/ltr}\times(300\text{ ltr})\\&=\$\,354\text{ USD}\end{aligned}$

Thus, the price of the fuel of the car in the complete trip in US dollars is $\boxed{\$\,354}$ .

Part (B):

Concept:

The distance covered by the car in covering one mile is equivalent to $1.61\text{ km}$ .

The amount of fuel consumed by the car in covering one mile is:

$\begin{aligned}v^{'}&=1.6\text{ km}\times\dfrac{6\text{ ltr}}{100\text{ km}}\\&=0.096\text{ ltr}\end{aligned}$

The volume of oil consumed in terms of gallons per mile is:

$\begin{aligned}v^{'}&=0.096\text{ ltr}\times\dfrac{1\text{ gallon}}{3.78\text{ ltr}}\\&=0.0254\text{ gallons}\end{aligned}$

Thus, the fuel consumed in gallons per mile is $\boxed{0.0254\text{ gallons/mile}}$ .

Learn More:

1. Forces of attraction limit the motion of particles most in brainly.com/question/947434

2. Acceleration of the red block after it is released brainly.com/question/6088121

3. The torque about the center of mass of the beam brainly.com/question/2506028

Answer Details:

Grade: High School

Subject: Physics

Chapter: Units and Measurement

Keywords:

Rental package, car, average consumption, euro, US dollar, USD, europe, fuel on your trip, fuel cost, 6 liter, 1.063 euros/liter.

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Answer:

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Part b: When the road has a maximum grade of 4%, the minimum stopping sight distance is 528.19 ft.

Explanation:

Part a

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Here

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t is the perception-reaction time given as 2.5 sec.
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Part b

When Road has a maximum grade of 4%

The stopping sight distance is given as

$SSD=1.47 ut +\frac{u^2}{30 (\frac{a}{g} \pm G)}$

Here

SSD is the stopping sight distance which is to be calculated.
u is the speed which is given as 60 mi/hr
t is the perception-reaction time given as 2.5 sec.
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So the minimum stopping sight distance for a road with 4% upgrade is 528.19 ft.

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So the minimum stopping sight distance for a road with 4% downgrade is 607.59 ft.

As the minimum distance is required for the 4% grade road, so the solution is 528.19 ft.

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