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saveliy_v [14]
3 years ago
9

Part A:

Physics
2 answers:
svetlana [45]3 years ago
8 0
Part A:
( 5,000 : 100 ) * 6 = 300 lit.
300 lit.  * 1.066 Euros/ lit. = 318.9 Euros
1 Euro = 1.20 USD
318.9 * 1.20 = 382.68 USD

Part B :
6 lit./100 km = 0.06 lit/1 km
1 gal = 3.7853 lit.
1 mile = 1.609344 km
0.06 : 3.7853 = 0.01585
... = 0.01585 gal / 1 km  / * 1.609344
= 0.0255 gal/mile
 
marissa [1.9K]3 years ago
3 0

(a). The fuel expense of the car in the complete trip in US dollars is \boxed{\$\,354}.

(b). The fuel consumed in gallons per mile is \boxed{0.0254\text{ gallons/mile}}.

Explanation:

Given:

The price of the fuel in Europe is 1.063\text{ euros/ltr}.

The amount of fuel required for every 100\text{ km} is 6.00\text{ ltr}.

<u>Part (A):</u>

Concept:

The value of one euro equivalent to the US dollar is \$\,1.11.

The cost of the fuel in terms of the US dollar is:

\begin{aligned}c&=1.063\text{ euros/ltr}\left(\dfrac{\$\,1.11}{1\text{ euro}}\right)\\&=\$\,1.18\text{ USD/ltr}\end{aligned}

Since the car consumes 6\text{ ltr} of fuel during the journey of 100\text{ km}, the total fuel consumed by the car in the trip of 5000\text{ km} is:

\begin{aligned}n&=\dfrac{6\text{ ltr}}{100\text{ km}}\times(5000\text{ km})\\&=300\text{ ltr}\end{aligned}

The fuel consumed by the car in the whole trip of 5000\text{ km} is 300\text{ ltr}.

The fuel expense for the trip of 5000\text{ km} can be obtained as:

\begin{aligned}\text{ cost}&=1.18\text{ USD/ltr}\times(300\text{ ltr})\\&=\$\,354\text{ USD}\end{aligned}

Thus, the price of the fuel of the car in the complete trip in US dollars is \boxed{\$\,354}.

<u>Part (B):</u>

Concept:

The distance covered by the car in covering one mile is equivalent to 1.61\text{ km}.

The amount of fuel consumed by the car in covering one mile is:

\begin{aligned}v^{'}&=1.6\text{ km}\times\dfrac{6\text{ ltr}}{100\text{ km}}\\&=0.096\text{ ltr}\end{aligned}

The volume of oil consumed in terms of gallons per mile is:

\begin{aligned}v^{'}&=0.096\text{ ltr}\times\dfrac{1\text{ gallon}}{3.78\text{ ltr}}\\&=0.0254\text{ gallons}\end{aligned}

Thus, the fuel consumed in gallons per mile is \boxed{0.0254\text{ gallons/mile}}.

<u />

Learn More:

1. Forces of attraction limit the motion of particles most in brainly.com/question/947434

2. Acceleration of the red block after it is released brainly.com/question/6088121

3. The torque about the center of mass of the beam brainly.com/question/2506028

Answer Details:

Grade: High School

Subject: Physics

Chapter: Units and Measurement

Keywords:

Rental package, car, average consumption, euro, US dollar, USD, europe, fuel on your trip, fuel cost, 6 liter, 1.063 euros/liter.

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A 75.0kg bicyclist (including the bicycle) is pedaling to the right, causing her speed to increase at a rate of 2.20m/s^2, despi
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1) 4 forces

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3) 225 N

Explanation:

1)

There are in total 4 forces acting on the bicylist:

- The gravitational force on the byciclist, acting vertically downward, of magnitude mg, where m is the mass of the bicyclist and g is the acceleration due to gravity

- The normal force exerted by the floor on the bicyclist and the bike, N, vertically upward, and of same magnitude as the gravitational force

- The force of push F, acting horizontally forward, given by the push exerted by the bicylist on the pedals

- The air drag, R, of magnitude R = 60.0 N, acting horizontally backward, in the direction opposite to the motion of the bicyclist

2)

The magnitude of the net force on the bicyclist can be calculated by considering separately the two directions.

- Along the vertical direction, we have the gravitational force (downward) and the normal force (upward); these two forces are equal in magnitude, since the acceleration of the bicyclist along this direction is zero, therefore the net force in this direction is zero.

- Along the horizontal direction, the two forces (forward force of push and air drag) are balanced, since the acceleration is non-zero, so we can use Newton's second law of motion to find the net force on the bicylist:

F_{net}=ma

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F_{net} is the net force

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3)

In this part, we basically want to find the forward force of push, F.

We can rewrite the net force acting on the bicyclist as

F_{net}=F-R

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F is the forward force of push

R is the air drag

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F_{net}=165 N is the net force on the bicyclist

R = 60.0 N is the magnitude of the air drag

Therefore, by re-arranging the equation, we can find the force generated by the bicylicst by pedaling:

F=F_{net}+R=165+60=225 N

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