Question

An object of mass 0.67 kg is attached to a spring with spring constant 15 N/m. If the object is pulled 14 cm from the equilibrium position and released.
What is the maximum speed of the object?

Answer 1

Answer:

The maximum speed of the object is 0.662 m/s.

Explanation:

Given that,

Mass of the object, m = 0.67 kg

Spring constant of the spring, k = 15 N/m

The spring is pulled 14 cm or 0.14 m from the equilibrium position and released.

To find,

The maximum speed of the object.

Solution,

The maximum speed of the object is given by :

$v=A\omega$........(1)

Where

$\omega=\sqrt{\dfrac{k}{m}}$

$\omega=\sqrt{\dfrac{15}{0.67}}$

$\omega=4.73\ rad/s$

So,

$v=0.14\times 4.73$

v = 0.662 m/s

So, the maximum speed of the object is 0.662 m/s.