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Nata [24]
3 years ago
14

What is the strength of the electric field 0.020 m from a 12 uc charge?

Physics
1 answer:
belka [17]3 years ago
5 0

Answer:

Option B is correct.

Explanation:

Given the charge, Q = 12uC

Now convert the uC into C = 5*10^-6 C

Given, d = 0.020 m

Now use the below formula:

E = K*Q/d^2

Now insert all the values in the above formula and then solve.

E = (9 ×10^9) × (12×10^-6) / (0.020)^2

E  = 2.7 ×10^8 N/C

Therefore option B is correct.

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If it's not accelerating, then the net force on it is zero.

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So the friction on the desk must be equal to your<em> 245N</em> .

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The answer A hope this helped

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Objects with equal speeds definitely have equal velocities. -- FALSE.  For equal velocities, they also have to be going in the same direction.

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If an object moves at constant velocity, it must also be moving at constant speed. -- TRUE.  Constant velocity means its speed AND its direction are not changing.

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After laboring through this one, I'm wondering if there can possibly be any more ways to say the same thing.

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Answer:

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A = Cross sectional area = 0.5 m²

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