Burn rate can be affected by: A. Variations in chamber pressure B. Variations in initial grain temperature C. Gas flow velocity
1 answer:
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Answer:
a) 158.4 HP.
b) 1235.6 °F.
Explanation:
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In this case, according to the given information, it turns out possible for us to set up an energy balance for the turbine's inlets and outlets:
Whereas the mass flow is just the same, which means we have:
And the enthalpy and entropy of the inlet stream is obtained from steam tables:
Now, since we assume the 80% accounts for the isentropic efficiency for this adiabatic gas turbine, we assume the entropy is constant so that:
Which means we can find the temperature at which this entropy is exhibited at 15 psia, which gives values of temperature of 1200 °F (s=2.1986 BTU/lbm-K) and 1400 °F (s=2.2604 BTU/lbm-K), and thus, we interpolate for s=2.2096 to obtain a temperature of 1235.6 °F.
Moreover, the enthalpy at the turbine's outlet can be also interpolated by knowing that at 1200 °F h=1639.8 BTU/lbm and at 1400 °F h=174.5 BTU/lbm, to obtain:
Then, the isentropic work (negative due to convention) is:
And the real produced work is:
Finally, in horsepower:
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