Answer:
It will not experience fracture when it is exposed to a stress of 1030 MPa.
Explanation:
Given
Klc = 54.8 MPa √m
a = 0.5 mm = 0.5*10⁻³m
Y = 1.0
This problem asks us to determine whether or not the 4340 steel alloy specimen will fracture when exposed to a stress of 1030 MPa, given the values of <em>KIc</em>, <em>Y</em>, and the largest value of <em>a</em> in the material. This requires that we solve for <em>σc</em> from the following equation:
<em>σc = KIc / (Y*√(π*a))</em>
Thus
σc = 54.8 MPa √m / (1.0*√(π*0.5*10⁻³m))
⇒ σc = 1382.67 MPa > 1030 MPa
Therefore, the fracture will not occur because this specimen can handle a stress of 1382.67 MPa before experience fracture.
Answer:
7
Explanation:
The structure of memory chip is given by multiplying the number of rows and column ie M X N
he number of address line required for row decoder is n where M =
or expressed in logarithmic form we have
In this case M=N since number of rows is equal to the number of columns
Therefore, 
Therefore,
M=128
Since 
Therefore, address lines should be at least 7
Answer:
The combination of GISs with associated data sources, such as remote sensing imagery, is now common in environmental monitoring and assessment. ... Using a GIS as an environmental modeling tool allows modelers to incorporate database capabilities, data visualization, and analytical tools in a single integrated environment.
Explanation:
I hope it helps...
Correct me if I'm wrong..
Answer: heat flux into the fun is 21.714 mW/m^2
Explanation:
Heat flux Q = q/A
q = heat transfer rate W
A = area m^2
q = area * conductivity * temperature gradient
Temperature gradient = difference in temperature of the metal faces divided by the thickness.
Therefore Q = k * ( temp. gradient)
Q = 200 * ((400-20)/3.5*10^-2)
Q = 21714285.71 = 21.714 mW/m^2
Answer 2: convective heat transfer flux between fin and air
is 3800W/m^2
Explanation :
q = hA*(Ts-Ta)
h = convective heat transfer coefficient
Ts = temperature of fin
Ta = temperature of air
Q = q/A
Q = h(Ts-Ta)
Q = 10(400 - 20)
Q = 3800 W/m^2
Answer:per minute from the pumping well, a steady state was attained in about 24 hr. The draw-down at a distance of 10 ft. was 5.5 ft. and at 25 ft. was 1.21 ft.
Explanation:
