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zalisa [80]
4 years ago
14

PLEASE HELP ME suppose you ride a bicycle around the ,returning to your starting point. At the end of your trip is your average

speed greater than, less than, or equal to the magnitude of your average velocity? Explain
Physics
1 answer:
lbvjy [14]4 years ago
7 0

Answer:

Greater than

Explanation:

Distance is the length of the path traveled.  Displacement is the difference between the final position and initial position.

Speed = distance / time

Velocity = displacement / time

Since you return to your starting point, your displacement is 0 m, so your average velocity is 0 m/s.  Therefore, your average speed is greater than your average velocity.

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Tamiku [17]
What are the choices?

4 0
4 years ago
An electric field of 1.27 kV/m and a magnetic field of 0.490 T act on a moving electron to produce no net force. If the fields a
lesantik [10]

Answer:

v = 2591.83 m/s

Explanation:

Given that,

The electric field is 1.27 kV/m and the magnetic field is 0.49 T. We need to find the electron's speed if the fields are perpendicular to each other. The magnetic force is balanced by the electric force such that,

qE=qvB\\\\v=\dfrac{E}{B}\\\\v=\dfrac{1.27\times 10^3}{0.49}\\\\v=2591.83\ m/s

So, the speed of the electron is 2591.83 m/s.

8 0
3 years ago
A truck covers 40.0 m in 7.45 s while uniformly slowing down to a final velocity of 3.50 m/s.
astra-53 [7]

Answer:

(A) Original velocity will be 7.244 m /sec

(B) Acceleration will be  -0.5026m/sec^2

Explanation:

We have given distance covers by truck s = 40 m

Time taken by truck to cover this distance t = 7.45 sec

Final velocity v = 3.50 sec

According to second equation of motion

S=ut+\frac{1}{2}at^2

40=u\times 7.45+\frac{1}{2}\times a\times 7.45^2

7.45u+27.751a=40-----eqn 1

According to first equation of motion

v = u + at

So 3.5=u+7.45a-----eqn2

Solving equation 1 and 2

a = -0.5026m/sec^2

And u = 7.244 m /sec

(A) Original velocity will be 7.244 m /sec

(B) Acceleration will be

-0.5026m/sec^2

6 0
4 years ago
A stone falls from rest from the top of a cliff. A second stone is thrown downward from the same height 2.7 s later with an init
Darina [25.2K]

Answer:4.05 s

Explanation:

Given

First stone is drop from cliff and second stone is thrown with a speed of 52.92 m/s after 2.7 s

Both hit the ground at the same time

Let h be the height of cliff and it reaches after time t

h=\frac{gt^2}{2}

For second stone

h=52.92\times \left ( t-2.7\right )+\frac{g\left ( t-2.7\right )^2}{2}---2

Equating 1 &2 we get

\frac{gt^2}{2}=52.92\times \left ( t-2.7\right )+\frac{g\left ( t-2.7\right )^2}{2}

\frac{g}{2}\left ( t-t+2.7\right )\left ( 2t-2.7\right )-\left ( t-2.7\right )52.92=0

13.23\times \left ( 2t-2.7\right )-\left ( t-2.7\right )52.92=0

26.46t-35.721-52.92t+142.884=0

t=4.05 s

4 0
3 years ago
What properties are in semiconductors ​
scoray [572]

Semiconductors are substances with properties somewhere between them. Conductors such as gold, silver and copper have low resistance and conduct electricity easily.

4 0
4 years ago
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