Explanation:
The given data is as follows.
= 120 V, 
= 6.50 V
= 400, 
= ?
Formula to calculate the number of turns in secondary coil are as follows.
Putting the given values into the above formula as follows.
= 21.66
= 22 (approx)
Thus, we can conclude that number of turns in the secondary coil are 22.
Answer:
<em>specific</em><em> </em><em>heat</em><em> </em><em>capacity</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>=</em>107.2J/kg K
Answer:
800
Explanation:
Focal length of telescope, F = 200cm
Focal length of eyepiece, f = 0.25
The magnifying power of a telescope is given as the ratio of the focal length of the objective of the telescope to the focal length of the lens. Mathematically:
M = F/f
Therefore, when F = 200cm and f = 0.25cm:
M = 200/0.25
M = 800
