Answer:
Friction force on the bullet is 58.7 N opposite to its velocity
Explanation:
As we know that initial speed of the bullet is 55 m/s
after travelling into the sand bag by distance d = 1.34 m it comes to rest
so final speed
now we can use kinematics top find the acceleration of the bullet
so we have
now by Newton's II law we know that
so we have
<h3>Hello There!!</h3>
<h3><u>Given</u>,</h3>
Force(F) = 150N
Mass(m) = 90kg
<h3><u>To </u><u>Find,</u></h3>
Acceleration(a) = ?
<h3><u>We know,</u></h3>
F= m×a
<h3>Hope this helps</h3>
I believe that is true.
hope this helps!
According to Newton's second Law of motion, if the mass of an object is 10 kg and the force is 10 newtons, then the acceleration is 1m/s².
<h3>How to calculate acceleration?</h3>
The acceleration of a moving body can be calculated by dividing the force of the body by its mass.
According to this question, the mass of an object is 10 kg and the force is 10 newtons, then the acceleration can be calculated as follows:
acceleration = 10N ÷ 10kg
acceleration = 1m/s²
Therefore, according to Newton's second Law of motion, if the mass of an object is 10 kg and the force is 10 newtons, then the acceleration is 1m/s².
Learn more about acceleration at: brainly.com/question/12550364
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