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3 years ago

What energy transfer will a stretched rubber band have when let go

Physics

1 answer:

GarryVolchara [31]3 years ago

3 0

Answer:

when the rubber band is realeased the potential energy is quickly converted to kinetic energy this is equal to one mass of the the rubber band multiplied by its velocity( in meters per second)

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Question 25

aniked [119]

Answer:

o The result of a chemical change is a different composition; in a physical change, the composition remains the same.

Explanation:

In a chemical change, new kinds of matter are produced although the atoms are the same.

For physical changes, no new kinds of matter formed. Only the state of substances changes.

Most chemical changes are usually irreversible
Physical changes are reversible in most parts.
Changes in state and form are salient characteristics of physical changes.
When new products are formed from the reactants, it is an indicator of a chemical change.

7 0

2 years ago

Which do you think will penetrate farther into a block of lead, x-rays, or gamma rays

disa [49]

Gamma rays because it has more penetrating power and frequency but shorter wavelength.

3 0

3 years ago

A car travels 200km in 3.0 hours. Determine the average velocity of the car

Masja [62]

Answer:

Explanation:

The average velocity of the car can be found by using the formula

$a = \frac{d}{t } \\$

d is the distance

t is the time taken

From the question we have

$a = \frac{200}{3} \\ = 66.66666...$

We have the final answer as

Hope this helps you

4 0

3 years ago

Find the kinetic energy of an electron whose de broglie wavelength is 34.0 nm.

dezoksy [38]

The De Broglie wavelength of the electron is
$\lambda=34.0 nm=34 \cdot 10^{-9} m$
And we can use De Broglie's relationship to find its momentum:
$p= \frac{h}{\lambda}= \frac{6.6 \cdot 10^{-34} Js}{34 \cdot 10^{-9} m}=1.94 \cdot 10^{-26} kg m/s$

Given $p=mv$ , with m being the electron mass and v its velocity, we can find the electron's velocity:
$v= \frac{p}{m}= \frac{1.94 \cdot 10^{-26} kgm/s}{9.1 \cdot 10^{-31} kg}= 2.13 \cdot 10^4 m/s$

This velocity is quite small compared to the speed of light, so the electron is non-relativistic and we can find its kinetic energy by using the non-relativistic formula:
$K= \frac{1}{2}mv^2= \frac{1}{2}(9.1 \cdot 10^{-31} kg)(2.13 \cdot 10^4 m/s)^2=2.06 \cdot 10^{-22} J$

3 0

3 years ago

Electromagnetic radiation consists of particles called:

Westkost [7]

Photons are particles of electromagnetic radiation.

8 0

3 years ago