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SVEN [57.7K]
4 years ago
5

Can a tank of oxygen gas ever be half empty? Explain

Chemistry
2 answers:
Ksivusya [100]4 years ago
5 0
Yes they can. That's why they sell refills for them
Tju [1.3M]4 years ago
5 0
<span>Yes, they can be half empty. Oxygen canister's contain different types of oxygen some are very pure. They are filled at very high pressures.</span>
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Cómo se clasifican los tipos de nutrientes​
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Existen 6 tipos de nutrientes: Glúcidos, Lípidos, Proteínas, Vitaminas, Agua y Sales minerales. Cada uno cumple unas funciones distintas, aportando los elementos necesarios para nuestras células.

6 0
2 years ago
What are elements represented by ?
makvit [3.9K]

A Chemical Symbol

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4 0
3 years ago
A train travels at a speed of 30 miles per hour. If 1 mile = 1.6 kilometers, how fast is the train traveling in kilometers per m
Alina [70]
The answer 
 the speed of <span>the train traveling in kilometers per minute can be found by using the following method:
v = </span><span>30 miles per hour
</span><span>1 mile = 1.6 kilometers

just do the calculus by changing miles to kilometers
 </span>1 mile = 1.6 kilometers, so 30 miles= 1.6 km x 30 = 48 km
 so the speed of the train is
v=30 miles / hour = 48km / h = 48km / 60 mn  = 0.8 km/ mn
the answer is
<span>C- 0.8 km/min</span> 
7 0
3 years ago
The molecule shown is a
Pani-rosa [81]

c is the answer a benzene

8 0
3 years ago
Ka/KbMIXED PRACTICE108.Calculate the [H3O+(aq)], the pH, and the % reaction for a 0.50 mol/L HCN solution. ([H3O+(aq)] = 1.8 x 1
NeTakaya

Answer:

a) [H₃O⁺] = 1.8x10⁻⁵ M

b) pH = 4.75

c) % rxn = 3.5x10⁻³ %

Explanation:

a) The dissociation reaction of HCN is:

HCN(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CN⁻(aq)

0.5 M - x                       x               x

The dissociation constant from the above reactions is given by:

Ka = \frac{[H_{3}O^{+}][CN^{-}]}{[HCN]} = 6.17 \cdot 10^{-10}

6.17 \cdot 10^{-10} = \frac{x*x}{(0.5 - x)}

6.17 \cdot 10^{-10}*(0.5 - x) - x^{2} = 0

By solving the above quadratic equation we have:

x = 1.75x10⁻⁵ M = 1.8x10⁻⁵ M = [H₃O⁺] = [CN⁻]

Hence, the [H₃O⁺] is 1.8x10⁻⁵ M.

b) The pH is equal to:

pH = -log[H_{3}O^{+}] = -log(1.75 \cdot 10^{-5} M) = 4.75    

Then, the pH of the HCN solution is 4.75.

c) The % reaction is the % ionization:

\% = \frac{x}{[HCN]} \times 100

\% = \frac{1.75 \cdot 10^{-5} M}{0.5 M} \times 100

\% = 3.5 \cdot 10^{-3} \%          

Therefore, the % reaction or % ionization is 3.5x10⁻³ %.

I hope it helps you!      

6 0
2 years ago
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