Explanation:
Helium is produced in radioactive process that occurs in deep and underground formations. They differ from other atmospheric gases. These radioactive decay of heavier nuclides that are unstable started about the time when the earth was formed.
- As they decay they give off lighter particles that can easily be broken down into more stable ones.
- One of the main product of the decay is alpha particles.
- They have the same atomic structure as helium
- These materials are trapped in underground formations.
Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
Explanation:
First we have to calculate the moles of diethyl ether

As, 1 mole of diethyl ether require heat = 26.5 kJ
So, 1.01 moles of diethyl ether require heat = 
Thus 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether
Answer:
14 moles
Explanation:
For an Ideal gas,
PV = nRT...................... Equation 1
Where P = Pressure, V = Volume, n = number of mole, R = Molar gas constant.
make n the subject of the equation
n = PV/RT.................. Equation 2
Given: P = 14.297 atm, V = 22.9 L = 22.9 dm³, T = 12 °C = (12+273) K = 285 K.
Constant: R = 0.082 atm.dm³/K.mol
Substitute these values into equation 2
n = (14.297×22.9)/(285×0.082)
n = 327.4013/23.37
n = 14.009
n ≈ 14 moles
Organic matter plays an important part in the local, regional, and global water cycles due to its role in promoting water.