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max2010maxim [7]
3 years ago
15

What force is needed to give a 0.25-kg arrow an acceleration of 196 m/s2? A. 0.25 N B. 49 N C. 196 N D. 748 N

Physics
2 answers:
Amanda [17]3 years ago
5 0
The answer is <span>B. 49 N</span>

Force is equal to the mass of that object multiplied by its acceleration:

F = m × a <span>
The unit of force is N = kg * m/s².

It is given:
m = 0.25 kg
a = 196 </span>m/s²
<span>
F = </span>m × a = 0.25 kg × 196 m/s² = 49 N<span>

</span>
Taya2010 [7]3 years ago
3 0

B.49 N is the ANSWER! I took the test on k12 and it was right

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The graph below shows the speed of a car as it drives along a racetrack.
nordsb [41]

Answer:

Average speed = distance/time

From 1 to 9 seconds:

Distance covered = 1 - 0.2 = 0.8 km

Time = 9 - 1 = 8 sec

Average speed = 0.8 km / 8 sec

Average speed = 0.1 km/s .

The average speed for the whole test is 1.6 km / 20 sec = 0.08 km/sec. A graph of speed vs time would average out as a horizontal line at 0.08 km/sec from 1 sec to 21 sec. The area under it would be (0.08 km/s) x (20 sec) = 1.6 km.

Surprise surprise ! The area under a speed/time graph is the distance covered during that time !

In closing, I want to express my gratitude for the gracious bounty of 3 points with which I have been showered. Moreover, the green breadcrust and tepid cloudy water have also been refreshing.

Explanation:

4 0
3 years ago
Homework help plz it would help a lot ​
blagie [28]

#82

here we know that

acceleration = 2 m/s/s

time = 5 s

initial speed = 4 m/s

now we can use kinematics to find the final speed

v_f = v_i + at

v_f = 4 + 2(5)

v_f = 14 m/s

So correct answer will be option D)

#83

here we know that

acceleration = 3 m/s/s

time = 4 s

initial speed = 5 m/s

now we can use kinematics to find the final speed

v_f = v_i + at

v_f = 5 + 3(4)

v_f = 17 m/s

So correct answer will be option C)

#84

here we know that

acceleration = 7 m/s/s

time = 3 s

initial speed = 8 m/s

now we can use kinematics to find the final speed

v_f = v_i + at

v_f = 8 + 7(3)

v_f = 29 m/s

So correct answer will be option C)

6 0
3 years ago
A sports car and a minivan run out of gas and are pushed to the side of the road. Which is easier to push, and why?
astraxan [27]

Answer:

The correct option is;

The sports car, because it has less mass and therefore less inertia

Explanation:

Newton's first law of motion states that an object will continue in its state of rest or uniform motion in a straight line unless acted on by a force. The property exhibited by the object is known as inertia

Newton's second law states that force is directly proportional to the rate of change of momentum produced

The rate of change of momentum of an object is directly proportional to the resultant force applied and is in the direction of the resultant force. The resultant force is equal to the rate of change of momentum.

Therefore, we have;

F = m·dv/dt = m×a

Given that the force required to move an object is directly proportional to its mass therefore, the inertia or the object resistance that requires a force to bring change is directly proportional to the mass of the object.

The mass of a sports car being considered lesser than the mass of the minivan will require less force to push and therefore has less inertia.

7 0
3 years ago
A constant force moves an object along the line segment from to . Find the work done if the distance is measured in meters and t
vladimir2022 [97]

This question is incomplete, the complete question is;

Flag

A constant force F = 6i+8j-6k moves an object along a straight line from point (6, 0, -10) to point (-6, 7, 2).

Find the work done if the distance is measured in meters and the magnitude of the force is measured in newtons.

Answer:

the work done is -88 J

Explanation:

Given the data in the question;

we know that;

Work done = F × S

where constant force F = ( 6i + 8j - 6k )

S = ( -6i + 7j + 2k ) - ( 6i + 0j - 10k )

S = ( (-6i - 6i) + (7j - 0j) + ( 2k - ( -10k) ) )

S = ( -12I + 7j + 12k )

so

Work force = ( 6i + 8j - 6k ) × ( -12I + 7j + 12k )

Work force = ( 6 × -12 ) + ( 8 × 7 ) + ( -6 × 12 )

Work force = -72 + 56 - 72

Work force = -88 J

Therefore, the work done is -88 J

8 0
3 years ago
In the classic horse and cart problem, a horse is attached to a cart that can roll along on a set of wheels. Which of the follow
Marina86 [1]
E is correct because net force in the forward direction is greater
4 0
3 years ago
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