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Juli2301 [7.4K]
3 years ago
12

Anxiety, moodiness, and feeling scared about the future are all common signs of

Physics
1 answer:
Brut [27]3 years ago
7 0
The answer would be distress
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How many cm3 are there in 1 dm3?
Verdich [7]

The answer is in the picture.

8 0
2 years ago
the brakes on a car do 240000j of work in stopping the car. if the car travels a distance of 40m while the brakes re being appli
Tpy6a [65]
A joule is one Newton of force applied over a meter.
For every meter, the brakes put 240000N of force (N=Newtons).
For 40m, multiply the Newtons by 40.
240000N*40=9600000N
3 0
3 years ago
What is the relationship between balancing equations and the law of conservation of matter
harkovskaia [24]
Every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. Therefore, there must be the same number of atoms of each element on each side of a chemical equation.
7 0
2 years ago
The ability of water molecules to form hydrogen bonds with other water molecules and water's ability to dissolve substances that
Arlecino [84]

Answer:

The ability of water molecules to form hydrogen bonds with other water molecules and water's ability to dissolve substances that have charges or partial charges are <u>due to water's partial charges.</u>

Explanation:

The partial negative charge on oxygen and partial positive charge on hydrogen enables them to make hydrogen bond and also makes it to dissolve the the other substances having partial charges.

4 0
2 years ago
A lead nucleus is spherical with a radius of about 7 ✕ 10⁻¹⁵ m. The nucleus contains 82 protons (and typically 126 neutrons). Be
Komok [63]

Answer:

∈=3.1584x10^{26} \frac{V}{m}

Explanation:

Using the Gauss Law to determine the electric field of the net flux at the surface of the nucleus

∈=\frac{P}{E_{o}}

The P is the charge density and 'Eo' is the constant of permittivity in free space

to find P

P=\frac{q}{V}

V=\frac{4}{3}*\pi*r^3

V=\frac{4}{3}\pi*(7x10^{-15})^3

V=2.932x10^{-14} m^3

P=\frac{82C}{2.932x10^{-14}m^3}=2.7965x10^{15} \frac{C}{m^3}

So replacing

∈=\frac{2.7965x10^{15}\frac{C}{m^3}}{8.8542x10^{-12}\frac{C^2}{N*m^2}}

∈=3.1584x10^{26} \frac{V}{m}

3 0
3 years ago
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