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4 years ago

Which of the following quantities are unknown?

Physics

1 answer:

Novay_Z [31]4 years ago

6 0

Answer:

unknow e and f

Explanation:

In experiments with alpha particles that are obtained by the method of radioactive decay of atoms, some parameters are known

a) Known. The initial velocity is given by the energy of the particles entities by the atomic nuclei

b) Known. The particle charge always 2e, helium core

c) Known. It is set in the given experiment, in general it is selected as zero

d) Known. Placed by the experimenter

e) Unknown. The speed depends on the interactions with the system

f) Unknown. It depends on the interactions with the system, because the position depends on the interactions

g) Known. It is always the value of a helium nucleo

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3 years ago

Which type of heat transfer causes your face to feel warm when you sit in the sun?

MA_775_DIABLO [31]

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4 years ago

A certain signal molecule S in heart tissue is degraded by two different biochemical pathways: when only Path 1 is active, the h

Misha Larkins [42]

Answer:

Half life of S = 3.76secs

Explanation:

The concept of half life in radioactivity is applied. Half life is the time taken for a radioactive material to decay to half of its initial size.

For part 1 - How much signal will be degraded in 1secs = 1/3.9 = 0.2564

for part 2 - How much signal will be degraded in 1secs = 1/104 = 0.009615

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6 0

3 years ago

The freezing point of a solution prepared by dissolving 150 × 10–3 g of caffeine in 10.0 g of camphor is lower by 3.07°C than th

Finger [1]

Answer:

Molar Mass=193.9738 g/mol

Molar Mass≅194g/mol

Explanation:

Consider the formula:

m=ΔT/K_{f}

where:

ΔT is freezing point depression

K_{f} is freezing point depression constant

m is the morality=(moles of solute/kg of solvent)

Now:

$m=\frac{3.07}{39.7}$

$m=0.07733 moles of solute/kg of solvent$

Now:

0.07733 (moles of solute/kg of solvent) *0.010 kg of solvent

$7.733*10^{-4}$ moles of solute(Caffeine)

Molar mass = Mass of solute/moles of solute

Molar Mass= $\frac{150*10^-3}{7.733*10^{-4} }$

Molar Mass=193.9738 g/mol

Molar Mass≅194g/mol

6 0

3 years ago