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irina [24]
4 years ago
13

If your mass is 20kg, and you stand on the scale (witch is your force), and the acceleration due to gravity is10m/s^2, what does

the scale says your weight is?
Physics
2 answers:
Sloan [31]4 years ago
8 0

Answer:

\Huge \boxed{\mathrm{200 \ N}}

Explanation:

\sf Weight \ (N)= mass \ (kg) \times acceleration \ of \ gravity \ (m/s^2)

W=mg

Your mass is 20 kg.

The acceleration of gravity is approximately 10 m/s².

W=20 \times 10

W=200

Your weight is 200 N.

Phantasy [73]4 years ago
5 0
Weight = (mass) x (gravity)

= 200 Newtons.

(About 44 pounds. You're very skinny.)
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Calculating heat gained or lost requires mass, specific heat, and
Anarel [89]
<span>Calculating heat gained or lost requires mass, specific heat, and

</span><span>c. change in temperature.</span><span>

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6 0
3 years ago
Similar to what you see in your textbook, you can generally omit the multiplication symbol as you answer questions online, excep
lidiya [134]

Answer:

ma= ma

m⋅a = m⋅a

And equivalently:

am=ma

a⋅m = m⋅a

Explanation:

Question

Assuming this question "Similar to what you see in your textbook, you can generally omit the multiplication symbol as you answer questions online, except when the symbol is  needed to make your meaning clear. For example, 1*10^5 is not the same as 110^5 . When you need to be explicit, type * (Shift + 8) to insert the multiplication operator. You will see a multiplication dot (⋅) appear in the answer box. Do not use the symbol x. For example, for the expression ma,

typing m⋅a would be correct, but mxa would be incorrect".

Solution to the problem

For this case we want to write a expression for ma, and based on the previous info we can write:

ma= ma

m⋅a = m⋅a

And equivalently:

am=ma

a⋅m = m⋅a

But is not correct do this:

mxa=mxa

axm = mxa

8 0
3 years ago
Read 2 more answers
Which of the following has a negative acceleration?
Volgvan

Answer:

B. A car sits at rest at a stop sign.

6 0
3 years ago
A 15.0 kg crate, initially at rest, slides down a ramp 2.0 m long and inclined at an angle of 20.0° with the horizontal. Using t
Elis [28]

The component of the crate's weight that is parallel to the ramp is the only force that acts in the direction of the crate's displacement. This component has a magnitude of

<em>F</em> = <em>mg</em> sin(20.0°) = (15.0 kg) (9.81 m/s^2) sin(20.0°) ≈ 50.3 N

Then the work done by this force on the crate as it slides down the ramp is

<em>W</em> = <em>F d</em> = (50.3 N) (2.0 m) ≈ 101 J

The work-energy theorem says that the total work done on the crate is equal to the change in its kinetic energy. Since it starts at rest, its initial kinetic energy is 0, so

<em>W</em> = <em>K</em> = 1/2 <em>mv</em> ^2

Solve for <em>v</em> :

<em>v</em> = √(2<em>W</em>/<em>m</em>) = √(2 (101 J) / (2.0 m)) ≈ 10.0 m/s

3 0
3 years ago
A5 cm object is 18.0 cm from a convex lens, which has a focal length of 10.0 cm.
Masja [62]

Explanation:

We have,

Height of object is 5 cm

Object distance from a convex lens is 18 cm

Focal length of convex lens is 10 cm

i.e. h = 5 cm

u = -18 cm

f = +10 cm

Let v is distance of the image from the lens. Using lens formula :

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{10}+\dfrac{1}{(-18)}\\\\v=22.5\ cm

The magnification of lens is :

m=\dfrac{v}{u}=\dfrac{h'}{h}, h' is height of the image

\dfrac{v}{u}=\dfrac{h'}{h}\\\\h'=\dfrac{vh}{u}\\\\h'=\dfrac{22.5\times 4}{(-18)}\\\\h'=-5\ cm

h' = -5.00 cm (in three significant figures)

6 0
3 years ago
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