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irina [24]
3 years ago
13

If your mass is 20kg, and you stand on the scale (witch is your force), and the acceleration due to gravity is10m/s^2, what does

the scale says your weight is?
Physics
2 answers:
Sloan [31]3 years ago
8 0

Answer:

\Huge \boxed{\mathrm{200 \ N}}

Explanation:

\sf Weight \ (N)= mass \ (kg) \times acceleration \ of \ gravity \ (m/s^2)

W=mg

Your mass is 20 kg.

The acceleration of gravity is approximately 10 m/s².

W=20 \times 10

W=200

Your weight is 200 N.

Phantasy [73]3 years ago
5 0
Weight = (mass) x (gravity)

= 200 Newtons.

(About 44 pounds. You're very skinny.)
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Protons and neutrons in an atom are held together by a nuclear energy also called the strong force.
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3 years ago
Starting from rest, approximately how far does an object fall freely in 3 seconds?
Sergio039 [100]
Hi! In 3 seconds the object will fall approximately 44 meters.
8 0
3 years ago
If the voltage across a circuit of constant resistance is doubled, the power dissipated by that circuit will
densk [106]

Answer:

The voltage will quadruple

Explanation:

The power dissipated in a circuit is given by

P=\frac{V^2}{R}

where

V is the voltage

R is the resistance

In this problem, the voltage across the circuit is doubled:

V' = 2V

So the new power dissipated is

P'=\frac{V'^2}{R}=\frac{(2V)^2}{R}=4\frac{V^2}{R}=4 P

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6 0
3 years ago
QUESTION 7
ryzh [129]

Answer:

<em>The force required is 3,104 N</em>

Explanation:

<u>Force</u>

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = ma

Where a is the acceleration of the object.

On the other hand, the equations of the Kinematics describe the motion of the object by the equation:

v_f=v_o+at

Where:

vf is the final speed

vo is the initial speed

a is the acceleration

t is the time

Solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

We are given the initial speed as vo=20.4 m/s, the final speed as vf=0 (at rest), and the time taken to stop the car as t=7.4 s. The acceleration is:

\displaystyle a=\frac{0-20.4}{7.4}

a=-2.757\ m/s^2

The acceleration is negative because the car is braking (losing speed). Now compute the force exerted on the car of mass m=1,126 kg:

F = 1,126\ kg * 2.757\ m/s^2

F= 3,104 N

The force required is 3,104 N

6 0
3 years ago
1) A 1,600 kilogram car is also traveling in a straight line. Its momentum is 32,500 kg*m/s. What is the
BaLLatris [955]

Answer:

v = 20.31 m/s

Explanation:

p = mv -> v = p/m = 32,500 kg*m/s / 1,600 kg = 20.31 m/s

4 0
2 years ago
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