Question

Wave A has an amplitude of 3, and wave B has an amplitude of 3. What will happen when the trough of wave A meets the trough of wave B?

Answer 1

Answer:

$A_r=6.$

Explanation:

It is given that both wave have same amplitude i.e $A=3.$

Now, we need to find what will happen to the waves when trough of wave A meets the trough of wave B.

It means that both waves are in same phase i.e, the phase difference between them is 0 degree.

We know resultant amplitude $A_r$ of two waves of same amplitude A with phase difference $\theta$ is given by.

$A_r=2\times A \times cos\dfrac{\theta}{2}.$

In this case , A=3 and $\theta=0^o.$

Putting value of A and $\theta$ in above equation.

We get, $A_r=6.$

Therefore, a new wave will form of resultant amplitude of 6.

Hence, it is the required solution.

Answer 2

The answer is: They will interfere to create a trough with an amplitude of 6.