What do the mitochondria do??

Physics

1 answer:

Ksju [112]3 years ago

4 0

Mitochondria breaks down sugar to release energy to the cell.

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A 55 kilogram person jumps off a cliff and hits the water 5.8 seconds later, how high is the cliff above the water?

dusya [7]

The cliff is 319. kilograms above the water

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2 years ago

Compressing the air by squeezing the bottle was accompanied by a(n) ________ in the temperature of air inside the bottle

Georgia [21]

Increase in temprature

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2 years ago

In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separatio

Keith_Richards [23]

Answer:

b. 0.25cm

Explanation:

You can solve this question by using the formula for the position of the fringes:

$y=\frac{m\lambda D}{d}$

m: order of the fringes

lambda: wavelength 500nm

D: distance to the screen 5 m

d: separation of the slits 1mm=1*10^{-3}m

With the formula you can calculate the separation of two adjacent slits:

$\Delta y=\frac{(m+1)(\lambda D)}{d}-\frac{m\lambda D }{d}=\frac{\lambda D}{d}\\\\\Delta y=\frac{(500*10^{-9}nm)(5m)}{1*10^{-3}m}=2.5*10^{-3}m=0.25cm$

hence, the aswer is 0.25cm

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2 years ago

Describe how to prepare a 10.0% w/v solution of salt in water in a 100 mL volumetric flask

Sphinxa [80]

To prepare a 10.0% w/v solution of salt in water in a 100 mL volumetric flask, first you must weigh 10 g of salt because the 10 % 100 is 10 and the given should be 10 % w/v. place the 10 g salt to the volumetric flask then add water up until to mark of the volumetric flask then shake it.

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2 years ago

You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a

zepelin [54]

Answer:

You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a furnace at 350.0 ∘C to a container of boiling water under 1 atmosphere.

Explanation:

Given Values:

L = 50 cm = 0.5 m

H = 170 j/s

To find the diameter of the rod, we have to find the area of the rod using the following formula.

Here Tc = 100.0° C

k = 50.2

H = k × A × $\frac{[T_{H -}T_{C} ] }{L}$