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3 years ago

Which would increase the rate of dissolving? Check all that apply.

2 answers:

8 0

The rate of dissolving would increase with:
<span>C) more surface area
</span><span>D) high temperature
</span><span>E) a lot of agitation
</span>

____ [38]3 years ago

3 0

Explanation:

Rate of dissolving is the rate at which a solute is able to dissolve in a solvent.

Some factors which affect the rate of dissolving are as follows.

More surface area : When there are more number of particles then it means there is more surface area of solute present in the solution. Thus, there will be more number of collisions between the solute and solvent molecules. As a result, rate of dissolving increases.

High temperature : More is the increase in temperature more will be the kinetic energy gained by molecules. Thus, this will lead to greater number of collisions and as a result, rate of dissolving increases.

Lot of agitation : When we stir a solution vigorously or create a disturbance then there will be increase in number of collisions which will also lead to increase in rate of dissolving.

Thus, we can conclude that the rate of dissolving would increase when there is:

more surface area.

high temperature.

a lot of agitation.

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There are 3.45 moles of (NH4)2 SO4, how many grams is this?

blsea [12.9K]

Answer:

455.4 g

Explanation:

Data given:

no. of moles of (NH₄)₂SO₄= 3.45 mol

mass of (NH₄)₂SO₄ = ?

Solution

Formula will be used

no.of moles = mass in grams / molar mass

Rearrange the above equation for mass

mass in grams = no. of moles x molar mass . . . . . . . . (1)

molar mass of (NH₄)₂SO₄

molar mass of (NH₄)₂SO₄ = 2(14 + 4(1)) + 32 + 4(16)

molar mass of (NH₄)₂SO₄ = 2 (14 +4) + 32 + 64

molar mass of (NH₄)₂SO₄ = 2 (18) + 32 + 64

molar mass of (NH₄)₂SO₄ = 36 + 32 + 64 = 132 g/mol

Put values in equation 1

mass in grams = 3.45 mole x 132 g/mol

mass in grams = 455.4 g

So,

mass of (NH₄)₂SO₄ = 455.4 g

8 0

3 years ago

water decomposes in an evacuated 2.00L container. If you started with 20.0 grams of water, determine the total resulting pressur

Deffense [45]

Resulting pressure is 13.6 atm.

<u>Explanation:</u>

Using Ideal gas equation, we can find the pressure of the gases formed in the reaction.

PV = nRT

Number of moles, n = given mass / molar mass = 20 g / 18 g/mol

= 1.11 moles

Volume, V = 2 L

Temperature, T = 25°C + 273 = 298 K

R = gas constant = 0.08206 L atm K⁻¹ mol⁻¹

P = nRT/V

= 1.11×0.08206 ×298 / 2

= 13.6 atm

5 0

4 years ago

which equation is set up correctly to determine the volume of a 1.5 mole sample of oxygen gas at 22 C and 100kPa

Murljashka [212]

Under STP condition, the gas has a rule of 22.4 L per mole. And according to the ideal gas law, V1/T1=V2/T2. Under STP, 1.5 mol gas has volume of 33.6 L. So the volume under 22 C is 33.6*295/273=36.3 L.

7 0

4 years ago

In-Lab Question 5a. Comparing your actual mass to the calculated target mass, would you predict the absorbance of your solution

Aleonysh [2.5K]

Answer:

less than

Explanation:

The absorbance of a solution is a function of the concentration (amount) of a substance in the solution. Mathematically, if the concentration is increased, the absorbance of the solution will also increase and if the concentration is decreased, the absorbance will decrease. There will be a decrease in the value of the absorbance because the calculated and predicted masses are not the same.

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3 years ago

This is a property of matter that can be identified without changing the identity of the substance.

Mrac [35]

<h3><u>Answer;</u></h3>

Physical property

<h3><u>Explanation;</u></h3>

A physical property is an aspect of matter that can be observed or measured without changing it. Examples of physical properties include color, shape, size, molecular weight and volume.
A chemical property on the other hand may only be observed by changing the chemical identity of a substance, that includes whether it can undergo a certain chemical change .

8 0

3 years ago

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