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elena55 [62]
3 years ago
10

A banked curve is designed for a roadway. The curve is designed so that a car traveling at 19.2 m/s can negotiate it without rel

ying on the force of static friction. The radius of the curve is 51.2 in and the car has a mass of 2300 kg. a. What angle is the curve banked at (degrees)? b. What is the magnitude of the Normal force (N) between the road and the car when it is traveling at the designed speed? c. If a careless driver tries to negotiate the curve at a speed of 25 m/s ,will the direction of the frictional force be inward or outward?
Physics
1 answer:
egoroff_w [7]3 years ago
8 0
I don’t know wait for someone else
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gizmo_the_mogwai [7]

Answer:

Acceleration,  767.08\ m/s^2

Explanation:

Given that,

Height from a ball falls the ground, h = 17.3 m

It is in contact with the ground for 24.0 ms before stopping.

We need to find the average acceleration the ball during the time it is in contact with the ground.

Firstly, find the velocity when it reached the ground. So,

v^2=u^2+2ah

u = initial velocity=0 m/s

a = acceleration=g

v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 17.3} \\\\v=18.41\ m/s

It is in negative direction, u = -18.41 m/s

Let a is average acceleration of the ball. Consider, v = and u = -18.41 m/s.

a=\dfrac{v-u}{t}\\\\a=\dfrac{0-18.41}{24\times 10^{-3}}\\\\a=767.08\ m/s^2

So, the average acceleration of the ball during the time it is in contact is 767.08\ m/s^2.

4 0
3 years ago
The 1.0-kg collar slides freely on the fixed circular rod. Calculate the velocity v of the collar as it hits the stop at B if it
soldi70 [24.7K]

Answer:

6.21 m/s

Explanation:

Using work energy equation then

U_{1-2}=T_B- T_A\\58d-mgh=0.5m(v_b^{2}-v_a^{2})

where d is displacement from initial to final position, v is velocity and subscripts a and b are position A and B respectively, m is mass of collar, g is acceleration due to gravity

Substituting 1 Kg for m, 0.4m for h, v_a as 0, 9.81 for g then

58(\sqrt{0.4^{2}+0.3^{2}}-0.1)-(1\times 9.81\times 0.4)=0.5\times 1\times (v_b^{2}-v_a^{2})\\19.276=0.5\times 1v_b^{2}\\v_b=6.209025688 m/s\approx 6.21 m/s

7 0
3 years ago
What is the distance from the crest to the equilibrium of a wave called? A. amplitude B. period C. frequency D. phase
Goryan [66]

its the first one. A.

8 0
3 years ago
Read 2 more answers
The even distribution of weight in a compostion is known as
mojhsa [17]
The answer is Balance. hopei helped? ahahahaha
3 0
3 years ago
Assertion(A):The distance moved by an object in unit time is called its speed. Reason (R):Faster vehicles have higher speeds. i)
ikadub [295]

Answer:

it's ii) R is correct while A is incorrect

Explanation:

cuz, both statements are correct but the reason is not the correct reason for the assertion,

8 0
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