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dusya [7]
4 years ago
12

Which one of the following does not accurately describe the universal gravitational law? A. Gravitational force is proportional

to the square of the distance between the centers of both bodies. B. The object with the smaller mass does most of the moving because the object with the larger mass has too much inertia to move any noticeable amount. C. Gravitational force is proportional to the product of the two masses. D. Every object in the universe that has mass attracts every other object in the universe that has mass.
Physics
2 answers:
meriva4 years ago
6 0
<span>A. Gravitational force is proportional to the square of the distance between the centers of both bodies.

FALSE:

Gravitational force is inversely proportional to the square of the distance between the centers of both bodies.

Which you can see from the formula: F = G * [m*M] /(d^2)

As you see in the equation, d^2 is in the denominator so the bigger d^2 (the square of the distance between the centers) of the objects the smaller the gravitational force.

B. The object with the smaller mass does most of the moving because the object with the larger mass has too much inertia to move any noticeable amount.

TRUE:

F = mass * acceleration => acceleration = F / mass => the larger the mass the smaller the acceleration.


C. Gravitational force is proportional to the product of the two masses.

TRUE:

F = G [m*M] / (d^2)

The product of the two masses, m*M, is in the numerator, so F is proportional to this product.

D. Every object in the universe that has mass attracts every other object in the universe that has mass.

TRUE: that is a Universal Law discovered by Sir Isaac Newton.
</span>
stiv31 [10]4 years ago
4 0
<span> Gravitational force is proportional to the square of the distance between the centers of both bodies.
</span>
* JUST TOOK THE TEST *
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Un cuerpo se mueve, partiendo del reposo, con una aceleración constante de 8 m/s². Calcular la velocidad que tiene al cabo de 5s
nataly862011 [7]

Answer:

v = 40 m / s

Explanation:

Let's use the expressions for accelerated motion

         v = v₀ + a t

where vo is the initial velocity, at the acceleration and t is the time.

as the body starts from rest its initial velocity is zero

         v = 0 + at

let's calculate

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         v = 40 m / s

8 0
3 years ago
Which organelle acts like the transportation or circulatory system of the cell?
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7 0
3 years ago
the length of iron rod at 100 C is 300.36 cm and at 159 C is 300.54 cm.Calculate its length at 0 c and coefficient of linear exp
Ugo [173]

Answer:

The length at 0 °C is 300.05 cm

Coefficient of linear expansion of iron is 1.02×10¯⁵ C¯¹

Explanation:

From the question given above, the following data were obtained:

Length (L₁) at 100 °C = 300.36 cm

Temperature 1 (θ₁) = 100 °C

Length (L₂) at 159 °C = 300.54 cm

Temperature 2 (θ₂) = 159 °C

Length (L₀) at 0 °C =?

Coefficient of linear expansion (α) =?

L₁ = L₀ (1 + θ₁α)

300.36 = L₀ (1 + 100α) ....(1)

L₂ = L₀ (1 + θ₂α)

300.54 = L₀ (1 + 159α) ..... (2)

Divide equation (2) by (1)

300.54 / 300.36 = L₀ (1 + 159α) / L₀ (1 + 100α)

1.0006 = (1 + 159α) / (1 + 100α)

Cross multiply

1.0006 (1 + 100α) = (1 + 159α)

1.0006 + 100.06α = 1 + 159α

Collect like terms

1.0006 – 1 = 159α – 100.06α

0.0006 = 58.94α

Divide both side by 58.94

α = 0.0006 / 58.94

α = 1.02×10¯⁵ C¯¹

Substitute the value of α into anything of the equation to obtain L₀. Here we shall use equation (2).

300.54 = L₀ (1 + 159α)

α = 1.02×10¯⁵ C¯¹

300.54 = L₀ (1 + 159 ×1.02×10¯⁵)

300.54 = L₀ (1 + 0.0016218)

300.54 = L₀ (1.0016218)

Divide both side by 1.0016

L₀ = 300.54 / 1.0016

L₀ = 300.05 cm

Summary:

The length at 0 °C is 300.05 cm

Coefficient of linear expansion of iron is 1.02×10¯⁵ C¯¹

6 0
3 years ago
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