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Scilla [17]
3 years ago
13

Juan is standing on the street. An ambulance moves toward him and then passes by. What best describes the pitch that Juan hears?

The pitch remains constant as the ambulance moves toward and then away from Juan. The pitch increases and decreases in a repeated pattern as the ambulance passes Juan. The pitch drops to a lower pitch once the ambulance passes by Juan. The pitch increases to a higher pitch once the ambulance passes by Juan.
Physics
2 answers:
avanturin [10]3 years ago
7 0

Answer:

C) The pitch drops to a lower pitch once the ambulance passes by Juan.

Explanation:

ozzi3 years ago
5 0

Answer: The correct answer is "the pitch drops to a lower pitch once the ambulance passes by Juan".

Explanation:

Doppler effect is the phenomenon in which there is an increase or decrease in the frequency when there is relative motion between the source and listener.

Pitch depends on the frequency. if the frequency increases then pitch increases.

When the source and the listener are moving towards each other then there is increase in the frequency. When the source and the listener are moving away each other then there is decrease in the frequency.

In the given problem, Juan is standing on the street. An ambulance moves toward him and then passes by the pitch drops to a lower pitch once the ambulance passes by Juan.

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the kinetic energy of an object of mass in moving with a velocity of 5 MS -1 is 25j what will be its kinetic energy when its vel
MAXImum [283]

Answer:

<em>When the speed is doubled, K = 100 J, when the speed is tripled, K = 225 J</em>

Explanation:

<u>Kinetic Energy </u>

Is the type of energy an object has due to its speed. It's proportional to the square of the speed.

The equation for the kinetic energy is:

\displaystyle K=\frac{1}{2}mv^2

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

The object has a kinetic energy of K=25 J when moving at v=5 m/s, thus the mass can be calculated by solving for m:

\displaystyle m=\frac{2K}{v^2}

\displaystyle m=\frac{2*25}{5^2}=2

m = 2 Kg

If the speed is doubled, v=10 m/s, the new kinetic energy is:

\displaystyle K=\frac{1}{2}2\cdot 10^2

K = 100 J

If the speed is tripled, v=15 m/s, the new kinetic energy is:

\displaystyle K=\frac{1}{2}2\cdot 15^2

K = 225 J

When the speed is doubled, K = 100 J, when the speed is tripled, K = 225 J

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An isolated parallel-plate capacitor has a surface charge density. If the space between the plates is filled with a material of
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Answer:

Explanation:

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A bicycle rider pushes a 13kg bicycle up a steep hill. the incline is 24 degree and the road is 275m long. the rider pushes the
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Answer:

A. W = 6875.0 J.

B. W = -14264.6 J.

Explanation:

A. The work done by the rider can be calculated by using the following equation:

W_{r} = |F_{r}|*|d|*cos(\theta_{1})

Where:                

F_{r}: is the force done by the rider = 25 N

d: is the distance = 275 m

θ: is the angle between the applied force and the distance

Since the applied force is in the same direction of the motion, the angle is zero.

W_{r} = |F_{r}|*|d|*cos(0) = 25 N*275 m = 6875.0 J

Hence, the rider does a work of 6875.0 J on the bike.

B. The work done by the force of gravity on the bike is the following:

W_{g} = |F_{g}|*|d|*cos(\theta_{2})  

The force of gravity is given by the weight of the bike.

F_{g} = -mgsin(24)     

And the angle between the force of gravity and the direction of motion is 180°.

W_{g} = |mgsin(24)|*|d|*cos(\theta_{2})  

W_{g} = 13 kg*9.81 m/s^{2}*sin(24)*275 m*cos(180) = -14264.6 J  

The minus sign is because the force of gravity is in the opposite direction to the motion direction.

Therefore, the magnitude of the work done by the force of gravity on the bike is 14264.6 J.  

I hope it helps you!                                                                                          

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