Which salt would be the most soluble in ice water?

The amount of erosion created by a river is affected by all of the following except

SashulF [63]

Answer:

This answer to this one should be Volume of Water.

5 0

3 years ago

Read 2 more answers

Name the types of motion represented by oA, AB and BC .

aivan3 [116]

Answer:

OA-Uniformly accelerated motion.
AB-constant speed,hence uniform motion.
BC-motion with uniform (-)ye acceleration.

8 0

3 years ago

You charge a parallel-plate capacitor, remove it from the battery, and prevent the wires connected to the plates from touching e

Ray Of Light [21]

Answer: a) C decreases; b) Q stays the same; c) E is the same

d) ΔV increase

Explanation: In order to explain this problem we have to consider the following:

C=εoA/d where A and d are the area and the separation of the plates, respectively.

Increasing d, produces a decrease of C.

Q remain constant becasuse the plates are charges and the wire are isoloted each other.

We also know that ΔV=E*d where E is electric field between the plates.

And E= Q/εo*A ( a constant between the plates)

As we can see from above, ΔV depends directely of the d so if d increase ΔV also increase. To do that we have to do work on the system.

7 0

4 years ago

Why are lighter cars allowed to drive on motorways at higher speeds than heavier ones?

daser333 [38]

Answer:

say a lighter car is going 80mph and a heavier car is going the same speed who do you think will have more damage i will say the heavier car

Explanation:

3 0

3 years ago

A uniformly charged, thin ring has radius 15.0 cm and total charge +24.0 nC. An electron is placed on the ring’s axis a distance

djyliett [7]

Answer:

A. The electron will begin to move along the axis, towards the centre and the instantaneous velocity because the force acting on it depends largely on acceleration and x until it reaches maximum velocity at centre.

B. Veloctiy (Vb) = 1.66m/s

Explanation:

Given the following data

x(a) = 0.3m

x(b) = 0

q = 1.6×10^-19

Q = 24nc

r = 0.15m

Required: the motion of the electron and the velocity (Vb)

1. At point A the electron will begin to move along the axis from point A to point B, the magnitude of the electric field will change while moving which depends on that and this will produce instantaneous force which will later change and the acceleration will change too while moving, the velocity would reach maximum value at point B

2. Potential energy and kinetic energy are given by

U(a) + K(a) = U(b) + K(b). . .1

Initial P.E and K.E are given as

U(a) = kQ/√x²(a) + a2

By substitution, we have

U(a) = 9×10^9 × (-1.9×10^-19)×24×10^-9/√(0.15)²+(0.3²)

U(a) = -1.03×10^-16

Final P.E and K.E are given as

U(b) = KQ/√x²(b) + a2

By substitution, we have

U(b) = 9×10^9×(-1.9×10^-19)×24×10^-9/√(0.15)²+(0)²

U(b) = -2.3×10^16

3. By substitution into equation 1 becomes

-1.03×10^-6 - 2.3×10^-16 + MV²(b)/2

V(b) = √2×1.27×10^-16/9.1×10^31

V(b) = 1.66×10^7m/s

4 0

4 years ago