Answer:
The percentage that of people who gave the movie a rating between 6.8 and 8.8
<em>P(6.8≤X≤8.8) = 83.9≅ 84 percentage</em>
Step-by-step explanation:
<u> Step(i):-</u>
Mean of the Population = 8.3 points
Standard deviation of the Population = 0.5 points
Let 'X' be the random variable in normal distribution
<em>Let X = 6.8</em>

Let X = 8.8

The probability that of people who gave the movie a rating between 6.8 and 8.8
<em>P(6.8≤X≤8.8) = P(-3≤Z≤1)</em>
= P(Z≤1)- P(Z≤-3)
= 0.5 + A(1) - ( 0.5 -A(-3))
= A(1) + A(3) (∵A(-3)=A(3)
= 0.3413 +0.4986 (∵ From Normal table)
= 0.8399
<u><em>Conclusion:-</em></u>
The percentage that of people who gave the movie a rating between 6.8 and 8.8
<em>P(6.8≤X≤8.8) = 83.9≅ 84 percentage</em>
Answer:3 minute
Step-by-step explanation:
Sakura speaks hungarian =150 words per minute
Sakura speaks polish =190 words per minute
and it is given she speaks 270 more words in polish than in hungarian
She speaks for a total of 5 minutes
let she speaks hungarian for t mins
therefore 
t=2 mins
therefore sakura speaks hungarian for 2 mins and polish for 3 mins
Answer:
7. RHS
8.RHS
9.SAS
10.SAS
11.RHS
12.ASA
Step-by-step explanation:
I conclude that the sum will be even because any even number can be represented by 2n where n is a whole number
and even numbers are 2 apart, so
the sum of the first 15 are
2n+2(n+1)+2(n+2) etc until we get to 2(n+14)
we can undistribute the 2 from all of them and get
2(n+n+1+n+2...n+14)
and we are sure that whatever is in the parenthasees is a whole number because whole+whole=whole
therefor, the sum is even
if you did want to find the sum then
an=2n
the 15th even number is 30
the first is 2
S15=15(2+30)/2=15(32)/2=15(16)=240
which is even
I think the correct answer from the choices listed above is the second option. Combining probabilities is a function of mutually exclusive events. Joint probability<span> is a measure of two events happening at the same time, and can only be applied to situations where more than one observation can be occurred at the same time.</span>