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3 years ago

8

Describe what happens between days 15-28 if the egg does not gets fertilized

1 answer:

dolphi86 [110]3 years ago

4 0

If the egg is fertilized by a man's sperm, the resulting embryo would travel down the fallopian tube and implant in the uterus. This happens around the 20th day of the menstrual cycle. ... Around day 26 of your cycle, the uterus will begin the process to shed its lining causing menstruation to begin

hope this helps

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Suppose that a certain atom possesses only four distinct energy levels. Assuming that all transitions between levels are possibl

olya-2409 [2.1K]

Answer:

Following are the response to the given question:

Explanation:

The number of shells

n = 4

Calculating the spectral line:

$= \frac{n(n-1)}{2}\\\\ = \frac{4(4-1)}{2} \\\\= \frac{4\times 3}{2}\\\\ = \frac{12}{2}\\\\ = 6$

4 0

2 years ago

How many grams of co2 is produced when oxygen reacts with carbon?

Serggg [28]

44g of CO2 can produce by the reaction of carbon with oxygen

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3 years ago

Problem Page Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.2 g o

stich3 [128]

Answer: 0.0 grams

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

a) moles of butane

$\text{Number of moles}=\frac{5.2g}{58.12g/mol}=0.09moles$

b) moles of oxygen

$\text{Number of moles}=\frac{32.6g}{32g/mol}=1.02moles$

$2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O$

According to stoichiometry :

2 moles of butane require 13 moles of $O_2$

Thus 0.09 moles of butane will require = $\frac{13}{2}\times 0.09=0.585moles$ of $O_2$

Butane is the limiting reagent as it limits the formation of product and oxygen is present in excess as (1.02-0.585)=0.435 moles will be left.

Thus all the butane will be consumed and 0.0 grams of butane will be left.

7 0

2 years ago

Write the molecular formula of nitrate using criss cross method <br><br><br><br>

exis [7]

Answer:

NO3 that is the answer to the question

8 0

3 years ago

77.In the early days of automobiles, illumination at night was provided by burning acetylene, C2H2. Though no longer used as aut

natta225 [31]

Answer:

554.86kj

Explanation: Since 1 mole of CaC2=15.14kj yield 1mole of C2H2

The enthalpy change of H2O is 2*285=570

570+-15.14=554.86kj

Hence Hp is 554.86kj

He=Hp

3 0

3 years ago

Read 2 more answers