A change that produces one or more ___________________ is a chemical change or chemical reaction.

Chemistry

2 answers:

posledela3 years ago

8 0

Answer:

New Substances. type that in.

Explanation:

Arada [10]3 years ago

4 0

Answer:

A change that produces one or more new substances is a chemical change or chemical reaction.

You might be interested in

Consider the reaction given below.

Drupady [299]

Answer:

K = 0.167 s⁻¹

Explanation:

1) Rate law, at a given temperature:

Since all the data are obtained at the same temperature, the equilibrium constant is the same.

Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

r = K [A]ᵃ [B]ᵇ

2) Use the data from the table

Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

Divide r₂ by r₁: [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

Use the first and second set of data to find the exponent a:

r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

2ᵃ = 2 ⇒ a = 1

3) Write the rate law

r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

4) Use any set of data to find K

With the first set of data

r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K = 0.167 s⁻¹

6 0

4 years ago

Determine the empirical formula for a compound that contains c, h and o. it contains 52.14% c and 34.73% o by mass.

Travka [436]

H %= 100- (52.14 + 34. 73) equals 13.13 %
Assuming 100 g of this compound
Mass H= 13.13 g
Moles H= 13.13 g ÷ 1.008g/ moles= 13

Mass C= 52.14 g
Moles C= 52.14 g ÷ 12.011 g/ moles= 4

The empirical formula is C4H1302

3 0

4 years ago

Read 2 more answers

How could an alpha particle pass straight through the metal foil and strike the center of the phosphor screen on the other side

djverab [1.8K]

I think you refer to Rutherford's Gold Foil Experiment alpha particles pass through because of the enormous amount of empty space inside the atom.

>>>more details here<<<
to have its trajectory affected the alpha particle has to pass "near" the nucleus to interact with the positive charge of the nucleus.
the fact is that internally the gold atoms are basically empty space and the nucleus represents only a small portion of the entire volume. only few alpha particles pass near the nucleus

picture added><><**><>< below}{<{>}
-gio-chealafi- hope this helps you, have a nice rest of the day. ily all!!