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Naily [24]
3 years ago
10

Jennifers bowling ball is dropped from rest. Janets bowling ball is thrown horizontally at the same time. After the balls are re

leased, is the acceleration of Jennifers bowling ball greater than, less than or equal to the acceleration of Janets bowling ball? Explain.
Physics
2 answers:
Pachacha [2.7K]3 years ago
8 0
They both have a constant acceleration of g (9.8 m/s) So they both have equal accelerations. This is according to the law of gravity 
lana66690 [7]3 years ago
7 0

Answer:

The acceleration of Jennifer’s bowling ball is equal to the acceleration of Janet’s bowling ball

Explanation:

Sometime around 1590, Galileo conducted a remarkable experiment by dropping two metal balls of equal density with different mass.

He found that gravity acts equally on all objects.

The acceleration due to gravity is a constant and is directed downward, regardless of the initial direction of the object.

So, the acceleration of Jennifer’s bowling ball is equal to the acceleration of Janet’s bowling ball.

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defon

Answer:

ml tayo 1v1 durugin kita

Explanation:

ano takot ml 1v1

6 0
3 years ago
What is the average velocity of atoms in 1.00 mol of neon (a monatomic gas) at 288k?
katovenus [111]

You could solve this in two ways: using the ideal gas law (Van der Waals parameters optional), or by using the density. Since you specify a pressure and temperature (in kelvin), I will use the ideal gas law. Ideal gas law: PV=nRT P = pressure = 1.00 ATM V = volume = 1.00 L n = moles = what you're solving for R = gas constant = 0.0821 L*ATM/(mol*T) (T is absolute temperature (kelvin)) T = absolute temperature = 298 K (1.00atm)(1.00L) = n(0.0821L*ATM*mol -1 T -1 )(298K) n = 0.04 moles A n = Avogadro's Number = number of molecules in one mole = 6.022141 * 10 23 0.04 * 6.022141*10 23 = 2.409 * 10 22 molecules of N 2 in 1.00L at 1.00atm and 298K

7 0
4 years ago
Two parallel wires are separated by 6.10 cm, each carrying 2.85 A of current in the same direction. (a) What is the magnitude of
Westkost [7]

Answer:

The force per unit length is 2.66 \times 10^{-5} \ N/m

Explanation:

The current carrying by each wires = 2.85 A

The current in both wires flows in same direction.

The gap between the wires = 6.10 cm

Now we will use the below expression for the force per unit length. Moreover, before using the below formula we have to change the unit centimetre into meter. So, we just divide the centimetre with 100.

F/l = \frac{\mu _0i_1 i_2}{2\pi d} \\i_1 = 2.85 \\i_ 2 = 2.85  \\\mu _0 = 4\pi \times 10^{-7} \\d = 0.061 \\F/l = \frac{4\pi \times 10^{-7} \times 2.85 \times 2.85}{2 \pi \times 0.061} \\= 2.66 \times 10^{-5} \ N/m

4 0
3 years ago
Please answer this im not sure
vovikov84 [41]

Answer:

the answer is B

8 0
3 years ago
An unstable atomic nucleus has a mass of 17.010-27kg, and starts out at rest. When it decays, it the original nucleus disintegra
slega [8]

Answer:

Part a)

v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s

Part b)

E = 4.4 \times 10^{-13} J

Explanation:

As per momentum conservation we know that there is no external force on this system so initial and final momentum must be same

So we will have

m_1v_1 + m_2v_2 + m_3v_3 = 0

(5 \times 10^{-27})(6 \times 10^6\hat j) + (8.4 \times 10^{-27})(4 \times 10^6\hat i) + (3.6 \times 10^{-27}) v = 0

(30\hat j + 33.6\hat i)\times 10^6 + 3.6 v = 0

v = -(8.33\hat j + 9.33\hat i)\times 10^6 m/s

Part b)

By equation of kinetic energy we have

E = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2 + \frac{1}{2}m_3v_3^2

E = \frac{1}{2}(5 \times 10^{-27})(6\times 10^6)^2 + \frac{1}{2}(8.4 \times 10^{-27})(4 \times 10^6)^2 + \frac{1}{2}(3.6 \times 10^{-27})(8.33^2 + 9.33^2) \times 10^{12}

E = 9\times 10^{-14} + 6.72 \times 10^{-14} + 2.82\times 10^{-13}

E = 4.4 \times 10^{-13} J

8 0
3 years ago
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