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almond37 [142]
4 years ago
6

Apakah soalan tingkatan 4 bm negeri selangor

Physics
1 answer:
noname [10]4 years ago
8 0
What does this mean? What do you need help with?
You might be interested in
Which is an inertial reference frame (or at least a very good approximation of one)? Which is an inertial reference frame (or at
ioda

Answer:

A jet plane flying straight and at level at constant speed

Explanation:

     The<em> inertial frame </em>of reference is a frame of reference in which all <em>Newton law  is valid</em> ie Newton second law of motion and therefore newton first law of motion holds good. <em>The frame of reference does not accelerate.</em>

All the object that is in the frame of reference are at rest or moving with constant rectilinear motion with constant velocity unless acted upon by any force.

4 0
3 years ago
What is a good example for newton's 1st law​
lesya692 [45]
A billiard ball. unless hit, the balls stay at rest. however when hit into another, the balls do not stop unless acted upon by another force.
5 0
3 years ago
Read 2 more answers
PLEASE HELP
hichkok12 [17]

The correct answer is 195.6 N

Explanation:

Different from the mass (total of matter) the weight is affected by gravity. Due to this, the weight changes according to the location of a body in the universe as gravity is not the same in all planets or celestial bodies. Moreover, this factor is measured in Newtons and it can be calculated using this simple formula W (Weight) = m (mass) x g (force of gravity). Now, leps calculate the weigh of someone whose mass is 120 kg and it is located on the moon:

F = 120 kg x 1.63 m/s2

F= 195.6 N

7 0
3 years ago
A ball is dropped from an aircraft flying at an altitude of 8,848 meters assuming gravity is 9.8m/s what is the total amount of
Dafna11 [192]
In this question, you're determining the time (t) taken for an object to fall from a distance (d).

The equation to represent this is:
Time equals the square root of 2 times the distance divided by the gravitational force of earth.
In equation from it looks like this (there isn't an icon to represent square root so just pretend like there's a square root there):
t = 2d/g (square-rooted)

d = 8,848m and g = 9.8m/s

Now plug in the information we have:
t = 2 x 8,848m/9.8m/s (square-rooted)

The first step is to multiply 2 times 8,848m:
t = 17,696m/9.8m/s (square-rooted)

Now divide 9.8m/s by 17,696m (note that the two m's (meters) cancels out leaving you with only s (seconds):
t = 1805.72s (square-rooted)

Now for the last step, find the square root of the remaining number:
t = 42.5s

So the time it takes the ball to drop from the height (distance) of 8,848 meters, and falling with the gravitational pull of 9.8 meters per second is 42.5 seconds.

I hope this helps :)

7 0
3 years ago
The top of lake is frozen as atmospheric temperature is -10 degree Celsius the temperature of the bottom of the lake is most lik
hjlf

4°Celcius Water is densest at 4°C

4 0
4 years ago
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