1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vinvika [58]
3 years ago
12

The box of a well-known breakfast cereal states that one ounce of the cereal contains 113 Calories (1 food Calorie = 4186 J). If

1.79% of this energy could be converted by a weight lifter's body into work done in lifting a barbell, what is the weight of the heaviest barbell that could be lifted a distance of 1.90 m?
Physics
2 answers:
zimovet [89]3 years ago
5 0

Answer:

4456.33N

Explanation:

Let the energy converted by the lifter's body into work done be E.

The work done in lifting the barbell is against gravity and it is given by equation (1);

work done=mgh..................(1)

where m is the mass of the barbell, g is acceleration due to gravity and h is the vertical distance (height) through which it is lifted. Hence by the principle of energy conversion as specified by the problem we could write the following equation;

E=mgh.....................(2)

Also, it should be recalled that the weight, W of an object is given by the equation below;

W=mg...............(3)

Substituting (3) into (2) we obtain the following;

E=Wh..................(4)

Given; h = 1.9m

To obtain the energy E converted by the lifter's body in Joules, we use the specifications given in the problem as follows;

Given; 1cal = 4186J

therefore 113cal = (113 x 4186)J = 473018J. This is the total energy contained in one ounce of cereal consumed by the lifter. However as specified by the problem, only 1.79% of this energy was converted by the lifter's body into weight lifting, therefore;

E=\frac{1.79}{100}*473018J=8467.02J

Putting this value of E into equation (4), we obtain the following;

8467.02=W*1.9\\

therefore;

W=\frac{8467.02}{1.9}=4456.33N

This is the heaviest weight of barbell the lifter could lift with the amount of energy specified.

mafiozo [28]3 years ago
3 0

Answer:

m=454.73 kg

Explanation:

To convert the energy of the cereal to know the weight:

m*g*h=Q'

Cal=0.0179*113 Cal=2.0227Cal

Q'=2.0227Cal*\frac{4186J}{1Cal}

m*g*h=8467.02J

m*g=\frac{Q'}{h}=\frac{8467.02J}{1.90m}

m*g=4456.33 N

Supuse the gravity as a g=9.8m/s^2

m=\frac{4456.33N}{9.8m/s^2}

m=454.73 kg

You might be interested in
A car takes 15 minutes to travel along a road that is 20 km long.
iogann1982 [59]

Answer:

C

Explanation:

15. 20

x4. x4

60. 80

80km/h

8 0
3 years ago
Read 2 more answers
A force of 8.0 N is along x direction, another force of 6.0 N is along +y direction. If both forces are acting on a point object
Darya [45]

Answer:

Resultant force, R = 10 N

Explanation:

It is given that,

Force acting along +x direction, F_x=8\ N

Force acting along +y direction, F_y=6\ N

Both the forces are acting on a point object located at the origin. Let the resultant force of the object is given by R. So,

R=\sqrt{F_x^2+F_y^2+F_xF_y\ cos\theta}

Here \theta=90^{\circ}

R=\sqrt{F_x^2+F_y^2}

R=\sqrt{8^2+6^2}

R = 10 N

So, the resultant force on the object is 10 N. Hence, this is the required solution.

6 0
3 years ago
A student is transmitting sound waves through various materials. Through which metal in the table will the sound waves travel th
MariettaO [177]

Answer:

Aluminum

Explanation:

promise

give  me brainlest plleaseee

5 0
2 years ago
Read 2 more answers
Manuel is holding a 5 kg box. How much force us the box exerting on him? in what direction
Free_Kalibri [48]
It will be 49 Newtons of force in the down direction. To find the force in newtons, you multiply the mass (5 kg) by the gravity (which if 9.8). 
3 0
3 years ago
What is the formula for the moment of inertia of the person/single particle rotating in a circle? (Give these values with a subs
Ann [662]

Moment of inertia of single particle rotating in circle is I1 = 1/2 (m*r^2)

The value of the moment of inertia when the person is on the edge of the merry-go-round is I2=1/3 (m*L^2)

Moment of Inertia refers to:

  • the quantity expressed by the body resisting angular acceleration.
  • It the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.

The moment of inertia of single particle rotating in a circle I1 = 1/2 (m*r^2)

here We note that the,

In the formula, r being the distance from the point particle to the axis of rotation and m being the mass of disk.

The value of the moment of inertia when the person is on the edge of the merry-go-round is determined with parallel-axis theorem:

I(edge) = I (center of mass) + md^2

d be the distance from an axis through the object’s center of mass to a new axis.

I2(edge) = 1/3 (m*L^2)

learn more about moment of Inertia here:

<u>brainly.com/question/14226368</u>

#SPJ4

7 0
2 years ago
Other questions:
  • Astronauts are trained for take-off in a high-speed centrifuge of 4.7 m radius that spins in the horizontal plane.
    6·1 answer
  • What is the best explanation of work?
    7·2 answers
  • Please Help!!! I'll make Brainliest
    12·1 answer
  • A series RLC circuit has a resistance of 57.61 W, a capacitance of 13.13 mF, and an inductance of 196.03 mH. The circuit is conn
    8·1 answer
  • What is the ratio of the sun’s gravitational pull on Mercury to the sun’s gravitational pull on the earth?
    14·1 answer
  • Arrange the following substances in order of decreasing magnitude of lattice energy. Rank the compounds in order of decreasing m
    13·2 answers
  • 7. An automobile with a radio antenna 1.0 m long travels at 100.0 km/h in a location where the Earth’s horizontal magnetic field
    6·1 answer
  • The small ball of mass m = 0.5 kg is attached to point A via string and is moving at constant speed in a horizontal circle of ra
    7·1 answer
  • Which type of fault occurs when rock is subjected to this type of stress
    10·1 answer
  • Please answer needed as soon as possible, will give brainlest...fill in the question mark area! No files, cant access on a schoo
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!