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3 years ago

Use these options to describe each genotype

Physics

1 answer:

Sliva [168]3 years ago

4 0

A homozygous dominant
B: homozygous recessive
C: heterozygous
I hope this helps you :)

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If a 16 N net force makes an object accelerate at 4 m/s2, what is the mass of the object?

12345 [234]

Answer:

4 kg

Explanation:

Acceleration = 4 m/s^2

Force = 16 N

Force = mass * acceleration

mass = force / acceleration

mass = 16 / 4

mass = 4 kg

4 0

2 years ago

Acceleration due to gravity on the moon is 1.6m/s^2 or about 16% of the value of gg on Earth. If an astronaut on the moon threw

xxTIMURxx [149]

To solve this problem it is necessary to apply the concepts related to the conservation of Energy. Mathematically the conservation of kinetic energy must be paid in the increase of potential energy or vice versa. This expressed in algebraic terms is equivalent to

Kinetic Energy = Potential Energy

$\frac{1}{2}mv^2 = mgh$

Where

m = Mass

v = Velocity

g = Gravity

h = Height

As the mass is the same then we have to

$\frac{1}{2} v^2 = gh$

Rearrange to find v,

$v = \sqrt{2gh}$

Our values are given as

$g = 1.6m/s^2$

$h = 7.8m$

Therefore replacing we have

$v = \sqrt{2(1.6)(7.8)}$

$v = 4.99m/s$

Hence the velocity at the moon would be 4.99m/s

The only direct affectation is that concerning the Resistance or drag force generated by a fluid - such as air in the ground - that can diminish / sharpen the direct effects of gravity. Disregarding the resistance of the air, as we can see in the equation previously given, there should be no affectation because the speed depends on the gravity and height.

5 0

3 years ago

What is NOT one of the three primary resources that families have to reach financial goals?

Elodia [21]

What is NOT one of the three primary resources that families have to reach financial goals? It is c) education

8 0

2 years ago

If the charge remains the same but the radius of the sphere is doubled, the electric flux coming out of it will be

il63 [147K]

Answer:

Explanation:

We shall apply Gauss's theorem for electric flux to solve the problem . According to this theorem , total electric flux coming out of a charge q can be given by the following relation .

∫ E ds = q / ε

Here q is assumed to be enclosed in a closed surface , E is electric intensity on the surface so

∫ E ds represents total electric flux passing through the closed surface due to charge q enclosed in the surface .

This also represents total flux coming out of the charge q on all sides .

This is equal to q / ε where ε is a constant called permittivity which depends upon the medium enclosing the charge . For air , its value is 8.85 x 10⁻¹² .

If charge remains the same but radius of the sphere enclosing the charge is doubled , the flux coming out of charge will remain the same .

It is so because flux coming out of charge q is q / ε . It does not depend upon surface area enclosing the charge . It depends upon two factors

1 ) charge q and

2 ) the permittivity of medium ε around .

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2 years ago

A mechanic needs to replace the motor for a merry-go-round. The merry-go-round should accelerate from rest to 1.5 rad/s in 7.0 s

marta [7]

Answer

given,

initial speed of merry-go-round = 0 rad/s

final speed of merry-go-round = 1.5 rad/s