Yo sup??
1 lmole of O2 contains 22.4 litre
therefore 10.2 miles will contain
=10.2*22.4
=228.48 litre
Hence the correct answer is option D
Hope this helps
Answer:
A tick living on a dog and drinking it's blood = Parasitism
Birds that live among cattle too eat insects stirred up by grazing = Mutualism
A clownfish living on the tentacles of an anemone provides nutrients too the anemone, and the clownfish is protected from predators = commensalism
A bear catching and eating a salmon from the river = predation
A bobcat catching and eating a rabbit = predation
A tapeworm living on the digestion system of a horse = parasitism
A Egyptian plover eating bugs off a giraffe or rhino = Mutualism
Bees gathering nectar and then spreading pollen too a flower = commensalism
Explanation:
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Answer:
a. 2,3-dimethylbutane < 2-methylpentane < n-hexane
Explanation:
The boiling point of alkanes is highly affected by the degree of branching in the molecule. Branched alkanes generally have a lower boiling point than unbranched alkanes.
The reason for the higher boiling point of unbranched alkanes is because they have greater vanderwaals forces acting between their molecules due to their larger surface area. Recall that branched alkanes have a lesser surface area compared to unbranched alkanes.
n-hexane is an unbranched alkane hence it will have the highest boiling point followed by 2-methyl pentane and lastly 2,3-dimethyl butane. The boiling point continues to decrease as the extent of branching increases.
Answer:
172.23L
Explanation:
Data obtained from the question include:
V1 (initial volume) = 200 L
P1 (initial pressure) = 0.94 atm
T1 (initial temperature) = 25°C = 25 + 273 = 298K
P2 (final pressure) = 1atm
T2 (final temperature) = 0°C = 0 + 273 = 273K
V2 (final volume) =?
Using the general gas equation P1V1/T1 = P2V2/T2, the final volume of the container can be obtain as follow:
P1V1/T1 = P2V2/T2
0.94 x 200/298 = 1 x V2/273
Cross multiply to express in linear form as shown below:
298 x V2 = 0.94 x 200 x 273
Divide both side by 298
V2 = (0.94 x 200 x 273)/298
V2 = 172.23L
The new volume of the container is 172.23L