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alex41 [277]
3 years ago
9

The two-second rule applies to any speed __________ A. in all weather conditions. B. in ideal weather and road conditions. C. in

the worst weather and road conditions. D. none of the above
Physics
2 answers:
kumpel [21]3 years ago
5 0

Answer:

The answer is A

Explanation:

A large risk of tailgating is the collision avoidance time being much less than the driver reaction time. Driving instructors advocate that drivers always use the "two-second rule" regardless of speed or the type of road. During adverse weather, downhill slopes, or hazardous conditions such as black ice, it is important to maintain an even greater distance.

Flura [38]3 years ago
5 0

Answer:

in ideal weather and road conditions.

Explanation:

Minimum Safe Following Distances

Leave plenty of space between you and the vehicle ahead, including bicycles. If it stops quickly, you will need time to see the danger and stop.

Using the Two-Second Rule

At any speed, you can use the two-second rule to see if you are far enough behind the car in front of you:

Watch the vehicle ahead pass some fixed point - an overpass, sign, fence corner, or other marker.

Count off the seconds it takes you to reach the same spot in the road ("one thousand and one, one thousand and two...").

If you reach the mark before you finish counting, you are following too closely. Slow down and check your following distance again.  

The two-second rule applies to any speed in ideal weather and road conditions. If road or weather conditions are not good, double your following distance. You should also double your following distance when driving a motor home or towing a trailer.

Following Distance For Trucks

A truck or any vehicle towing another vehicle may not follow within 300 feet of another truck or vehicle towing a vehicle. This law does not apply to overtaking and passing, and it does not apply within cities or towns.

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3 years ago
A spherical capacitor contains a charge of 3.40 nC when connected to a potential difference of 240.0 V. Its plates are separated
I am Lyosha [343]

Answer:

A) 1.4167 × 10^(-11) F

B) r_a = 0.031 m

C) E = 3.181 × 10⁴ N/C

Explanation:

We are given;

Charge;Q = 3.40 nC = 3.4 × 10^(-9) C

Potential difference;V = 240 V

Inner radius of outer sphere;r_b = 4.1 cm = 0.041 m

A) The formula for capacitance is given by;

C = Q/V

C = (3.4 × 10^(-9))/240

C = 1.4167 × 10^(-11) F

B) To find the radius of the inner sphere,we will make use of the formula for capacitance of spherical coordinates.

C = (4πε_o)/(1/r_a - 1/r_b)

Rearranging, we have;

(1/r_a - 1/r_b) = (4πε_o)/C

ε_o is a constant with a value of 8.85 × 10^(−12) C²/N.m

Plugging in the relevant values, we have;

(1/r_a - 1/0.041) = (4π × 8.85 × 10^(−12) )/(1.4167 × 10^(-11))

(1/r_a) - 24.3902 = 7.8501

1/r_a = 7.8501 + 24.3902

1/r_a = 32.2403

r_a = 1/32.2403

r_a = 0.031 m

C) Formula for Electric field just outside the surface of the inner sphere is given by;

E = kQ/r_a²

Where k is a constant value of 8.99 × 10^(9) Nm²/C²

Thus;

E = (8.99 × 10^(9) × 3.4 × 10^(-9))/0.031²

E = 3.181 × 10⁴ N/C

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How does the diaphragm remove air from the lungs?
LekaFEV [45]

Answer:

d) When the diaphragm pushes upward, it decreases the volume of the lungs, pushing air out.

Explanation:

the relaxed diaphragm muscle is dome-shaped, the contracted muscle is horizontal.

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2 years ago
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