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Margaret [11]
2 years ago
5

A certain lead-acid storage battery has a mass of 30 kg. starting from a fully charged state, it can supply 5 a for 24 hours wit

h a terminal voltage of 12 v before it is totally discharged.
a. if the energy stored in the fully charged battery is used to lift the battery with 100-percent efficiency, what height is attained? assume that the acceleration due to gravity is 9.8 m/s2 and is constant with height. b if the stored energy is used to accelerate the battery with 100 percent efficiency, what velocity is attained?
c. gasoline contains about 4.5 x 107 j/kg. compare this with the energy content per unit mass for the fully charged battery.

Physics
1 answer:
QveST [7]2 years ago
5 0
Check the attached file for the answer.

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Two cars collide at an intersection. One car has a mass of 1600 kg and is
pickupchik [31]

The combined momentum is 4000 kg m/s south

Explanation:

The total combined momentum of the two cars is given by the vector addition of the momenta of the two cars.

For this problem, we choose north as positive direction and south as negative direction.

The momentum of the first car travelling north is given by:

p_1 = m_1 v_1

where

m_1 = 1600 kg is the mass of the car

v_1 = +8 m/s is its velocity

Substituting,

p_1 = (1600)(8)=+12800 kg m/s

The momentum of the second car travelling south is given by:

p_2 = m_2 v_2

where

m_2 = 1400 kg is the mass of the car

v_2= -12 m/s is its velocity (negative because the car travels south)

Substituting,

p_2 = (1400)(-12)=-16800 kg m/s

And therefore, the combined momentum is

p=p_1 + p_2 = +12800 + (-16800)=-4000 kg m/s

where the negative sign means the direction of the total momentum is south.

Learn more about momentum:

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4 0
3 years ago
A student pushes on a 20.0 kg box with a force of 50 N at an angle of 30° below the horizontal. The box accelerates at a rate of
PtichkaEL [24]

Answer:

225 N

Explanation:

"Below the horizontal" means he's pushing down at an angle.

Draw a free body diagram of the box.  There are three forces: normal force N pushing up, weight force mg pulling down, and the applied force F at an angle θ.

Sum of forces in the y direction:

∑F = ma

N − mg − F sin θ = 0

N = F sin θ + mg

Plug in values:

N = (50 N) (sin 30°) + (20.0 kg) (10 m/s²)

N = 225 N

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3 years ago
Seema knows the mass of a basketball. What other information is needed to find the ball’s potential energy? the volume and heigh
Wewaii [24]

 It is because the potential energy is similar to MgH.

 When it comes to MgH, it means mass, gravity and height respectively.

 By using the value of acceleration, seema will find the potential energy of a ball.



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