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3 years ago

Explain in 3 or 4 sentences how materials are sorted by nature.

Physics

1 answer:

mojhsa [17]3 years ago

3 0

Their are lots of things that are not made by nature. FOOD ,WATER IRON , AND OTHER THINGS

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On a spacecraft, two engines are turned on for 789 s at a moment when the velocity of the craft has x and y components of v0x =

ddd [48]

Answer:

Explanation:

Given

time for which spacecraft turned on is 789 s

$v_{0x}=5410 m/s$

$v_{0y}=8100 m/s$

$x=2.78\times 10^6 m$

$y=4.73\times 10^6 m$

we know $s=ut+\frac{at^2}{2}$

$2.78\times 10^6=5410\times 789+\frac{a_x(789)^2}{2}$

$2.78=4.268+a_x\times 0.622$

$a_x=-2.392 m/s^2$

For y component

$s=ut+\frac{at^2}{2}$

$4.73\times 10^6=8100\times 789+\frac{a_y(789)^2}{2}$

$4.73=6.39+a_y\times 0.622$

$a_y=-2.66 m/s^2$

4 0

4 years ago

After a long night of cramming for a test, your college roommate hits his head forcefully against the wall of your room in despa

sweet [91]

Answer:

See the answer below

Explanation:

Newton's third law states that for every action, there will always be an opposing reaction of equal magnitude to the action.

<em>Hence, the wall will exert an equal opposing force to the head and the roommate will feel this opposing force as pains and/or headache. </em>

3 0

3 years ago

Juan compró un carro que dicen que es muy rápido. Cuándo lo probó recorrió una distancia de 4500m en tan solo 5 min. ¿Qué veloci

sweet [91]

Answer:

Don't know sorry..................

4 0

3 years ago

2) A man squeezes a pin between his thumb and finger, as shown in Fig. 6.1.

Salsk061 [2.6K]

<h3>pressure = force / area</h3>

<h3>force = 84 N</h3><h3>pressure = 6 × 10 - 5 = 55 m2</h3>

<h3>pressure = 84 / 55</h3>

<h3>pressure = 1.53 pascals</h3>

hope that helps and please tell me if i am wrong :)

8 0

3 years ago

When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is

padilas [110]

Answer:

$P_{C} = 3.2\, atm$

Explanation:

Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:

Bulb A (2 L, 2 atm) - Before opening:

$P_{A} \cdot V_{A} = n_{A} \cdot R_{u} \cdot T$

Bulb B (3 L, 4 atm) - Before opening:

$P_{B} \cdot V_{B} = n_{B} \cdot R_{u} \cdot T$

Bulbs A & B (5 L) - After opening:

$P_{C} \cdot (V_{A} + V_{B}) = (n_{A} + n_{B})\cdot R_{u} \cdot T$

After some algebraic manipulation, a formula for final pressure is derived:

$P_{C} = \frac{P_{A}\cdot V_{A} + P_{B}\cdot V_{B}}{V_{A}+V_{B}}$

And final pressure is obtained:

$P_{C} = \frac{(2\,atm)\cdot (2\,L)+(4\,atm)\cdot(3\,L)}{5\,L}$

$P_{C} = 3.2\, atm$

5 0

3 years ago