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julia-pushkina [17]
3 years ago
5

Explain in 3 or 4 sentences how materials are sorted by nature.

Physics
1 answer:
mojhsa [17]3 years ago
3 0
Their are lots of things that are not made by nature. FOOD ,WATER IRON , AND OTHER THINGS
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On a spacecraft, two engines are turned on for 789 s at a moment when the velocity of the craft has x and y components of v0x =
ddd [48]

Answer:

Explanation:

Given

time for which spacecraft turned on is 789 s

v_{0x}=5410 m/s

v_{0y}=8100 m/s

x=2.78\times 10^6 m

y=4.73\times 10^6 m

we know s=ut+\frac{at^2}{2}

2.78\times 10^6=5410\times 789+\frac{a_x(789)^2}{2}

2.78=4.268+a_x\times 0.622

a_x=-2.392 m/s^2

For y component

s=ut+\frac{at^2}{2}

4.73\times 10^6=8100\times 789+\frac{a_y(789)^2}{2}

4.73=6.39+a_y\times 0.622

a_y=-2.66 m/s^2

4 0
4 years ago
After a long night of cramming for a test, your college roommate hits his head forcefully against the wall of your room in despa
sweet [91]

Answer:

See the answer below

Explanation:

Newton's third law states that for every action, there will always be an opposing reaction of equal magnitude to the action.

<em>Hence, the wall will exert an equal opposing force to the head and the roommate will feel this opposing force as pains and/or headache. </em>

3 0
3 years ago
Juan compró un carro que dicen que es muy rápido. Cuándo lo probó recorrió una distancia de 4500m en tan solo 5 min. ¿Qué veloci
sweet [91]

Answer:

Don't know sorry..................

4 0
3 years ago
2) A man squeezes a pin between his thumb and finger, as shown in Fig. 6.1.
Salsk061 [2.6K]
<h3>pressure = force / area</h3>

<h3>force = 84 N</h3><h3>pressure = 6 × 10 - 5 = 55 m2</h3>

<h3>pressure = 84 / 55</h3>

<h3>pressure = 1.53 pascals</h3>

hope that helps and please tell me if i am wrong :)

8 0
3 years ago
When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is
padilas [110]

Answer:

P_{C} = 3.2\, atm

Explanation:

Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:

Bulb A (2 L, 2 atm) - Before opening:

P_{A} \cdot V_{A} = n_{A} \cdot R_{u} \cdot T

Bulb B (3 L, 4 atm) - Before opening:

P_{B} \cdot V_{B} = n_{B} \cdot R_{u} \cdot T

Bulbs A & B (5 L) - After opening:

P_{C} \cdot (V_{A} + V_{B}) = (n_{A} + n_{B})\cdot R_{u} \cdot T

After some algebraic manipulation, a formula for final pressure is derived:

P_{C} = \frac{P_{A}\cdot V_{A} + P_{B}\cdot V_{B}}{V_{A}+V_{B}}

And final pressure is obtained:

P_{C} = \frac{(2\,atm)\cdot (2\,L)+(4\,atm)\cdot(3\,L)}{5\,L}

P_{C} = 3.2\, atm

5 0
3 years ago
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