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3 years ago

Name the component used in electric circuits that is sensitive to temperature

Physics

1 answer:

ahrayia [7]3 years ago

5 0

Answer :

<h3><em>Tungsten</em><em> </em><em>filament </em></h3>

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The electric force between two charged objects depends on which of the following

emmainna [20.7K]

<span>The electric force between two charged objects depends on
the product of their charges and the distance between them.</span>

6 0

2 years ago

Read 2 more answers

The distance between two successive maximaof

denpristay [2]

Answer:

v = 1.224 m/s

Explanation:

given,

distance between the two successive maxima = 1.70 m

number of crest = 8

time = 11 s

frequency is equal to number of cycle per secod

$f = \dfrac{8}{11}$

$f = 0.72\ Hz$

velocity of wave

v = f x λ

v = 0.72 x 1.70

v = 1.224 m/s

Hence, the wave speed is equal to v = 1.224 m/s

4 0

3 years ago

Which of the following is least likely to result from seafloor spreading

Assoli18 [71]

Answer:

An reversal in the magnetic fields of the north and south pole. This would be the most logical option for me...correct me if I'm wrong.

Explanation:

New seafloor is formed when magma is forced upward toward the surface at a mid-ocean.

7 0

3 years ago

A rigid container holds 0.30g of hydrogen gas.

Strike441 [17]

Answer:

Part A: $\mathbf{Q =94 \ J}$ to two significant figures

Part B: $\mathbf{Q =160 \ J}$ to two significant figures

Part C: $\mathbf{Q =220 \ J}$ to two significant figures

Explanation:

Given that :

mass of the hydrogen = 0.30 g

the molar mass of hydrogen gas molecule = 2 g/mol

we all know that:

number of moles = mass/molar mass

number of moles = 0.30 g /2 g/mol

number of moles = 0.15 mol

For low temperature between the range of 50 K to 100 K, the specific heat at constant volume for a diatomic gas molecule = $C_v=\dfrac{3}{2}R$

For Part A:

$Q = mC_v\Delta T$

$Q= 0.15 \ mol (\dfrac{3}{2})(8.314 \ J/mole.K )(100-50)K$

$Q= 0.15 \times (\dfrac{3}{2}) \times (8.314 \ J )\times (50)$

$Q=93.5325 \ J$

$\mathbf{Q =94 \ J}$ to two significant figures

Part B. For hot temperature, $C_v=\dfrac{5}{2}R$

$Q = mC_v\Delta T$

$Q= 0.15 \ mol (\dfrac{5}{2})(8.314 \ J/mole.K )(300-250)K$

$Q= 0.15 \times (\dfrac{5}{2}) \times (8.314 \ J )\times (50)$

$Q=155.8875 \ J$

$\mathbf{Q =160 \ J}$ to two significant figures

Part C. For an extremely hot temperature, $C_v=\dfrac{7}{2}R$

$Q = mC_v\Delta T$

$Q= 0.15 \ mol (\dfrac{7}{2})(8.314 \ J/mole.K )(2300-2250)K$

$Q= 0.15 \times (\dfrac{7}{2}) \times (8.314 \ J )\times (50)$

$Q=218.2425 \ J$

$\mathbf{Q =220 \ J}$ to two significant figures

6 0

3 years ago

skateboarder, starting from rest, rolls down a 13.5 m ramp. When she arrives at the bottom of the ramp her speed is 7.37 m/s. If

scZoUnD [109]

Answer:

1.7 m/s²

Explanation:

d = length of the ramp = 13.5 m

v₀ = initial speed of the skateboarder = 0 m/s

v = final speed of the skateboarder = 7.37 m/s

a = acceleration

Using the equation

v² = v₀² + 2 a d

7.37² = 0² + 2 a (13.5)

a = 2.01 m/s²

θ = angle of the incline relative to ground = 29.9

a' = Component of acceleration parallel to the ground

Component of acceleration parallel to the ground is given as

a' = a Cosθ

a' = 2.01 Cos29.9

a' = 1.7 m/s²

7 0

3 years ago