Cyan and magenta mixed together will give you B) BLUE.
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Answer : 413.44N
Here it is given that an elevator is moving down with an acceleration of 3.36 m/s² . And we are interested in finding out the apparent weight of a 64.2 kg man . For the diagram refer to the attachment .
- From the elevator's frame ( non inertial frame of reference) , we would have to think of a pseudo force.
- The direction of this force is opposite to the direction of acceleration the frame and its magnitude is equal to the product of mass of the concerned body with the acceleration of the frame .
- When a elevator accelerates down , the weight recorded is less than the actual weight .
From the Free body diagram ,
- Mass of the man = 64.2 kg
Answer:
The volume of the balloon would be (580.12m) cm^3
Explanation:
From the ideal gas equation,
PV = nRT
P is pressure in the balloon = 742 mmHg = 742/760 = 0.976 atm
V is the volume of the balloon
n is the number of moles of carbon dioxide in the balloon. Let the mass of carbon dioxide be m.
n = mass/MW = m/44 = (0.023m) mol
R is gas constant = 82.057 cm^3.atm/mol.K
T is temperature of the balloon = 27 °C = 27 + 273 = 300 K
V = 0.023m × 82.057 × 300/0.976 = (580.12m) cm^3
Answer:
0.037 N/m
Explanation:
The web acts as a spring, so it obeys Hook's law:
(1)
where
F is the force exerted on the web
k is the spring constant
x is the stretching/compression of the web
In this problem, we have:
- The mass of the fly is
- The force exerted on the web is the weight of the fly, so:
- The stretching of the web is
So if we solve eq.(1) for k, we find the spring constant: