Name the component used in electric circuits that is sensitive to temperature

Physics

1 answer:

ahrayia [7]3 years ago

5 0

Answer :

<h3><em>Tungsten</em><em> </em><em>filament </em></h3>

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Calculate the critical angle for light going from Glycerine to air.

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The refractive index for glycerine is $n_g=1.473$ , while for air it is $n_a = 1.00$ .

When the light travels from a medium with greater refractive index to a medium with lower refractive index, there is a critical angle over which there is no refraction, but all the light is reflected. This critical angle is given by:
$\theta_c = \arcsin ( \frac{n_2}{n_1} )$
where n1 and n2 are the refractive indices of the two mediums. If we susbtitute the refractive index of glycerine and air in the formula, we find the critical angle for this case:
$\theta_c = \arcsin ( \frac{1.00}{1.473} )=42.8^{\circ}$

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The balmer series is formed by electron transitions in hydrogen that

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Answer:

The Balmer series refers to the spectral lines of hydrogen, associated to the emission of photons when an electron in the hydrogen atom jumps from a level $n \geq 3$ to the level $n=2$ .

The wavelength associated to each spectral line of the Balmer series is given by:

$\frac{1}{\lambda}=R_H (\frac{1}{2^2}-\frac{1}{n^2})$

where $R_H$ is the Rydberg constant for hydrogen, and where $n$ is the initial level of the electron that jumps to the level n = 2.

The first few spectral lines associated to this series are withing the visible part of the electromagnetic spectrum, and their wavelengths are:

656 nm (red, corresponding to the transition $3 \rightarrow 2$ )

486 nm (green, $4 \rightarrow 2$ )

434 nm (blue, $5 \rightarrow 2$ )

410 nm (violet, $6 \rightarrow 2$ )

All the following lines lie in the ultraviolet part of the spectrum. The limit of the Balmer series, corresponding to the transition $\infty \rightarrow 2$ , is at 364.6 nm.